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JulsSmile [24]
3 years ago
9

Y squared + 5y - 84 equals what

Mathematics
1 answer:
iragen [17]3 years ago
7 0

The two possibilities for y are y = -12 and y = 7.

In order to solve this, we first just factor the equation. In order to factor a quadratic like this, we look for factors of the last number (-84) that add up to the middle number (5). In order to find that, we just need to list the factors.

1 * -84

-1 * 84

2 * -42

-2 * 42

3 * -28

-3 * 28

4 * -21

-4 * 21

7 * -12

- 7 * 12

This last factor is the one that adds to 5. Now we stick these two numbers along with y's into parenthesis.

(y - 7)(y + 12)

Now to solve, we can set each parenthesis equal to 0 to solve.

y - 7 = 0

y = 7

y + 12 = 0

y = -12

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2 years ago
. If f(x) = 3x - x, what is the value of f(7 - 2)?
kifflom [539]

Answer:

10

Step-by-step explanation:

f(x) =3x-x=2x,

f(7-2)=f(5)= 2*5=10

4 0
3 years ago
Use the difference of squares pattern to factor the polynomial.x2 − 16y2 how would I do this
love history [14]
The general rule for difference of two squares is that when factorised it can be written in the form (a+b)(a-b) where a is the square root of the first part of the function and b is the square root of the second part of the function.
From this we can find the square root of x² to find a and the square root of 16y² to find b.
In this case √x²=x and √16y²=4y
Therefore fully factorised it can be written as (x+4y)(x-4y)
6 0
3 years ago
A number divided by 43 has a quotient of 3 with 28 as a remainder. Find the number. Show your work. Write another division probl
antiseptic1488 [7]

A quotient of 3 with 28 as a remainder means that 43 fits inside our number 3 times, and you have 28 more units as a remainder.

So, our number is

3\times 43 + 28 = 129+28=157

To write another division problem that has a quotient of 3 and a remainder of 28, we simply choose another number to substitute 43 in the expression above. For example, if we choose 100, the expression becomes

3\times 100 + 28 = 300+28=328

Which means that 328 has quotient of 3 with 28 as a remainder when divided by 100.

4 0
3 years ago
Find S9, the sum of the geometric series to the 9th term, in which a3=3.645 and a8=15
ArbitrLikvidat [17]

Answer:

The sum of the first nine terms of the sequence is 74.44.

Step-by-step explanation:

Geometric sequence concepts:

The nth term of a geometric sequence is given by the following equation.

a_{n+1} = ra_{n}

In which r is the common ratio.

This can be expanded for the nth term in the following way:

a_{n} = a_{1}r^{n-1}

In which a_{1} is the first term.

Or even:

a_{n} = a_{m}r^{n-m}

The sum of the first n terms of a geometric sequence is given by:

S_{n} = \frac{a_{1}(1 - r^{n})}{1 - r}

Finding the common ratio:

a_{3} = 3.645, a_{8} = 15

a_{n} = a_{m}r^{n-m}

a_{8} = a_{3}r^{8-3}

a_{3}r^{5} = a_{8}

3.645r^{5} = 15

r^{5} = \frac{15}{3.645}

r = \sqrt[5]{\frac{15}{3.645}}

r = 1.327

Finding the first term:

a_{3} = a_{1}r^{2}

a_{1} = \frac{a_{3}}{r^{2}}

a_{1} = \frac{3.645}{(1.327)^{2}}

a_{1} = 2.07

Sum of the first nine terms:

S_{9} = \frac{2.07*(1 - (1.327)^{9})}{1 - 1.327} = 74.44

The sum of the first nine terms of the sequence is 74.44.

8 0
3 years ago
Read 2 more answers
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