<span>Simplifying
6(x + 1) + 5 = 13 + -2 + 6x
Reorder the terms:
6(1 + x) + 5 = 13 + -2 + 6x
(1 * 6 + x * 6) + 5 = 13 + -2 + 6x
(6 + 6x) + 5 = 13 + -2 + 6x
Reorder the terms:
6 + 5 + 6x = 13 + -2 + 6x
Combine like terms: 6 + 5 = 11
11 + 6x = 13 + -2 + 6x
Combine like terms: 13 + -2 = 11
11 + 6x = 11 + 6x
Add '-11' to each side of the equation.
11 + -11 + 6x = 11 + -11 + 6x
Combine like terms: 11 + -11 = 0
0 + 6x = 11 + -11 + 6x
6x = 11 + -11 + 6x
Combine like terms: 11 + -11 = 0
6x = 0 + 6x
6x = 6x
Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x
Combine like terms: 6x + -6x = 0
0 = 6x + -6x
Combine like terms: 6x + -6x = 0
0 = 0
Solving
0 = 0
Couldn't find a variable to solve for.
This equation is an identity, all real numbers are solutions.</span>
Answer: 10
Step-by-step explanation:
Just divide 40 by 4 and you get 10
Your answer is 0.0909090909 if I'm not mistaken.
Answer:
9. 75°
10. 60°
Step-by-step explanation:
Note the angle-intercept theorem. If you create an angle in the opposite side of a circle from 2 points on other side, the arc will have a measure TWICE that of the intercepted angle created on other side.
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<u>Question 9</u>
Arc WX has a measure 76, thus the angle created is Angle V, which should be HALF of that. So angle V is 76/2 = 38
Now looking at the triangle inside the circle, we know three angles of a triangle add up to 180, thus we can write and solve for "?" angle:
X + W + V = 180
? + 67 + 38 = 180
? + 105 = 180
? = 180 - 105 = 75°
<u>Question 10</u>
Using the theorem we can say that Angle B is HALF of ARC XYZ.
So,
2*Angle B = Arc XY + Arc YZ
2*102 = Arc XY + 124
204 = Arc XY + 124
Arc XY = 204 - 124 = 80°
Also, Arc BX + Arc XY is twice that of Angle Z (which is 70), thus
Arc BX + Arc XY = 70 *2
Arc BX + Arc XY = 140
Arc BX + 80 = 140
Arc BX = 140 - 80 = 60°
