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stepladder [879]
3 years ago
11

What is the factor expression of 12p+30

Mathematics
2 answers:
ipn [44]3 years ago
8 0

Answer:

6(2p + 5)

Step-by-step explanation:

The largest common factor of 12 and 30 is 6.  Thus,

12p+30 = 6(2p + 5)

lesantik [10]3 years ago
3 0

Answer:

12x +30=6(2x+5)

Step-by-step explanation:

Find the Greatest Common Factor (GCF)

GCF = 6

Factor out the GCF (Write the GCF first and then in parenthesis, divide each term by the GCF)

6(12p/6 + 30/6)

Simplify each term that is within the parenthesis

6(2p + 5)

(hope this helps can i plz have brainlist :D hehe)

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Step-by-step explanation:

7^2+8^2=113

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How can i change 3.25 into fraction. also how can i change .115 into fraction
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Which value of m will create a system of parallel lines with no solution? y=mx-6 8x-4y=12 A coordinate grid with one line labele
nydimaria [60]

Answer:

A system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2

Step-by-step explanation:

The equation of the given line is 8·x - 4·y = 12

Which gives;

8·x- 12= 4·y

y = 2·x - 3

Given that the line passes through the points (0, -3) and (1, -1), we have;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

When (x₁, y₁) = (0. -3) and (x₂, y₂) = (1, -1), we have;

Slope, \, m =\dfrac{(-1)-(-3)}{1-(0)} = 2

y - (-3) = 2×(x - 0)

y = 2·x - 3 which is the equation of the given line

For the lines 8·x - 4·y = 12, which is the sane as y = 2·x - 3 and the line y = m·x  - 6 to have no solution, the slope of the two lines should be equal that is m = 2

Given that the line passes through the point (1.5, 0), we have;

y - 0 = 2×(x - 1.5)  

y = 2·x - 3...................(1)

For the equation, y = m·x  - 6, when m = 2, we have;

y = 2·x  - 6..................(2)

Solving equations (1) and (2) gives;

2·x - 3 = 2·x  - 6, which gives;

2·x - 2·x=  - 3 - 6

0 = 9

Therefore, a system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2.

4 0
3 years ago
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