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Alenkasestr [34]
3 years ago
15

How many diagonals can be drawn in the shape below? 7 8 9 10

Mathematics
1 answer:
vladimir2022 [97]3 years ago
4 0
There are 9 diagonals.

Please see the attached picture for all the vertices that are drawn.  When you start drawing the diagonals, be cautious of the ones that you have already drawn.

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What is 2 to the fourth power plus 81 minus 50 plus 5?
Taya2010 [7]

Answer:52


Step-by-step explanation:

2^4 = 16

Then..

16+81 =97

Then..

97-50 = 47

Lastly..

47+5 = 52

4 0
3 years ago
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Which of the following is most likely the next step in the series?<br> A.
wolverine [178]

Answer:

D.

Step-by-step explanation:

If you look at the pattern, the first shape (square) has four sides. Then, you have 5 sides, and finally, 6 sides.


Thus, a pattern of 4, 5, 6. So, the next shape must have 7 sides, leaving the only possible answer as D.

7 0
2 years ago
☆15 POINTS AND MARKED BRAINLIEST IF CORRECT☆<br>look at the image above to view the question!​
swat32

Answer:

3125 bacteria.

Step-by-step explanation:

We can write an exponential function to represent the situation.

We know that the current population is 100,000.

The population doubles each day.

The standard exponential function is given by:

P(t)=a(r)^t

Since our current population is 100,000, a = 100000.

Since our rate is doubling, r = 2.

So:

P(t)=100000(2)^t

We want to find the population five days ago.

So, we can say that t = -5. The negative represent the number of days that has passed.

Therefore:

\displaystyle P(-5)=100000(2)^{-5} = 100000 \Big( \frac{1}{32}\Big)  = 3125 \text{ bacteria}

However, we dealing within this context, we really can't have negative days. Although it works in this case, it can cause some confusion. So, let's write a function based on the original population.

We know that the bacterial population had been doubling for 5 days. Let A represent the initial population. So, our function is:

P(t)=A(2)^t

After 5 days, we reach the 100,000 population. So, when t = 5, P(t) = 100000:

100000=A(2)^5

And solving for A, we acquire:

\displaystyle A=\frac{100000}{2^5}=3125

So, our function in terms of the original day is:

P (t) = 3125 (2)^t

So, it becomes apparent that the initial population (or the population 5 days ago) is 3125 bacteria.

3 0
3 years ago
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Three times a number plus 12 minus 5 times the same number is 22. what is the number ?
Debora [2.8K]
3x+12-5=22
3x+7=22
3x=15
x=5
6 0
3 years ago
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Find the area of each composite figure. Use 3.14 for π. Round to the nearest tenth if necessary. What is the correct label?
maria [59]

Answer:im nl the best but i ngl think its 12.3 for the big one

Step-by-step explanation:

4 0
3 years ago
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