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Annette [7]
3 years ago
12

How do you find the 50th term of the sequence of 5,-2,-9,-16......

Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0

To find the 50th term in this sequence, first you need to find how what the sequence is. To get from 5 to -2 you're subtracting 7, to get from -2 to -9, you subtract another 7. In order to get the next number you go down by multiples of 7: 5 - 7 = -2; 5 - 14 = -9 and so on). So all you have to do is multiply 7 by 50 to get 350 and subtract that from 5 to get -345.


Hope this helps,

♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥

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Gnom [1K]

is the answer open circle?

7 0
3 years ago
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2. Give the degree of x2 - 17x + 2x - 5.00
Evgen [1.6K]

Answer:

2

Step-by-step explanation:

Degree is the highest power of a term

I hope im right!

5 0
3 years ago
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In a recent game butler school basketball team took 20 three point shots they made 35% of the shots they took how many three-poi
BaLLatris [955]
All you simply have to do is multiply 20 x 0.35. Multiplying it by 0.35 will turn it into the number that makes up 35%. The answer would be they made 7 shots.
4 0
4 years ago
Find the center and radius of the circle x^2+y^2=49
Alex_Xolod [135]
The circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r". 
Therefore the radius is √49=7 and the center coordinates are (0,0)
6 0
4 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
Luda [366]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n



now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605


Hence answer is approx 1606 beetles will be there after 10 years.


To find answer for 20 years plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549


Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(1000\right)}{\log\left(1.32\right)}=n24.8810001465=n


Hence answer is approx 25 years.

8 0
3 years ago
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