Answer:
By creating some crops that resist certain insects
Step-by-step explanation:
Answer:
The constant factor remains a multiplier.
Step-by-step explanation:
The derivative of "a·f(x)" is a·f'(x). That is, the constant multiplier remains a constant multiplier, unchanged.
For ax^-1, the derivative is a(-x^-2) per the power rule. For your value of a=-5/2, this is ...
![\dfrac{d}{dx}\left(-\dfrac{5}{2x}\right)=\left(-\dfrac{5}{2}\right)\left(\dfrac{-1}{x^2}\right)=\dfrac{5}{2x^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Cleft%28-%5Cdfrac%7B5%7D%7B2x%7D%5Cright%29%3D%5Cleft%28-%5Cdfrac%7B5%7D%7B2%7D%5Cright%29%5Cleft%28%5Cdfrac%7B-1%7D%7Bx%5E2%7D%5Cright%29%3D%5Cdfrac%7B5%7D%7B2x%5E2%7D)
Area of ABC : AB*AC/2
the maximum of the parabola is reached at x=-4/(2*(-1))=2 hence A is at (2,0) and B is at (2,(-2)^2+4*2+C)=(2,12+C)
C is the second root (x-intersect), which we can find :
determinant1 : D=16-4*(-1)*C=4(4+C) thus the second root is at x=
![\frac{-4-\sqrt{4(4+C)}}{-2}=2+\sqrt{4+C}](https://tex.z-dn.net/?f=%5Cfrac%7B-4-%5Csqrt%7B4%284%2BC%29%7D%7D%7B-2%7D%3D2%2B%5Csqrt%7B4%2BC%7D)
Hence the area of the triangle is
![AB*AC/2=(4+C)*(2+\sqrt{4+C}-2)/2=(4+C)\sqrt{4+C}/2=32](https://tex.z-dn.net/?f=AB%2AAC%2F2%3D%284%2BC%29%2A%282%2B%5Csqrt%7B4%2BC%7D-2%29%2F2%3D%284%2BC%29%5Csqrt%7B4%2BC%7D%2F2%3D32)
hence
![(4+C)\sqrt{4+C}=64](https://tex.z-dn.net/?f=%284%2BC%29%5Csqrt%7B4%2BC%7D%3D64)
.
We remark that
![64=16*4=16*\sqrt{16}](https://tex.z-dn.net/?f=64%3D16%2A4%3D16%2A%5Csqrt%7B16%7D)
Hence 4+C=16 thus
C=12
Answer:
18 divided by 6 = 3.
Step-by-step explanation: