Answer:
Option A
Step-by-step explanation:
Area of the composite figure = Area of ΔABH + Area of BCGH + Area of ΔDEF
Area of ΔABH = 
= 
= 9 in²
Area of the trapezoid = 
= 
= 25 in²
Area of ΔDEF = 
= 24 in²
Therefore, area of the given figure = 9 + 25 + 24
= 58 in²
Option A will be the correct option.
Answer: 65,780
Step-by-step explanation:
When we select r things from n things , we use combinations and the number of ways to select r things = 
Given : The total number of playing cards in a deck = 52
The number of different five-card hands possible from a deck = 2,598,960
In a deck , there are 26 black cards and 26 red cards.
The number of ways to select 5 cards from 26 cards = 

Hence, the number of different five-card hands possible from a deck of 52 playing cards such that all are black cards = 65,780
Answer:
A
Step-by-step explanation:
a = 3n-30 solve for 'n'
a + 30 = 3n
n = (a+30)/3
n(a) = (a+30)/3
Step-by-step explanation:
i. (2x+10)+(3x+5)+(2x+40) = 360
2x+3x+2x+10+5+40= 360
7x+55 =360
7x=360-55
<u>7x</u>= <u>3</u><u>05</u>
7. 7
x= 43.57=43.6
ii. 2x+10= 180
2x=180-10
<u>2</u><u>x</u>= <u>1</u><u>7</u><u>0</u>
2. 2
x=85
3x+5 =180
3x=180-5
<u>3</u><u>x</u>=<u>1</u><u>7</u><u>5</u>
3. 3
x= 57.5
2x+40=180
2x=180-40
<u>2x</u>=<u>140</u>
2. 2
x= 70
From the above 3x+5 which is 57.5 is the smallest interior angle of the triangle
iii. The largest interior angle of the triangle is 2x+10 which is 85
Answer:
Options (E) and (G).
Step-by-step explanation:
From the data given in the table,
There is a common difference of $100 in every successive term of the amount of money.
Therefore, graph of the given table will represents a linear graph.
There are two points (5, 1200) and (6, 1300) lying on the graph.
Let the equation of the line is,

If A = Amount of money
n = Number of months

where 'n' = slope of the line
Slope = 
= 
= 100
Equation of the line passing through (6, 1300) and slope = 100
A - 1200 = 100(m - 5)
A = 100(m - 5) + 1200
A = 100m - 500 + 1200
A = 100m + 700
Therefore, Options (E) and (G) are the correct options.