Answer:
I just looked it up on google and it said to create journal entries...
Step-by-step explanation:
hope this helps... but idk
X times S = $27. X is the cost of the large sacks and S is the amount of sacks. Once they are multiplied it should equal $27. If this is incorrect please let me know so I can try and correct mistakes made.
Answer: c = 3
Step-by-step explanation: Distribute 0.2 to (10-5c)
2-1c=5c-16
Then subtract 2 on both sides and subtract the 5c.
-1c=5c-18
-6c=-18
Then divide -6 to -18
-18/-6 = 3
Suppose we have had S visitors in n months since EIS (Entry Into Service) of the site, then :
<span>S(n) = 8100 + 8100 * 3 + 8100 * 3^2 + 8100 * 3^3 + ... +8100 * 3^n </span>
<span>S(n) = 8100 * [ 1 + 3 + 3^2 + 3^3 + ... + 3^n ] </span>
<span>and we know that : </span>
<span>1 + 3 + 3^2 + 3^3 + ... + 3^n = (3^(n+1) - 1)/(3 - 1) </span>
<span>= (3^(n+1) - 1)/2 </span>
<span>therefore </span>
<span>S(n) = 8100 * (3^(n+1) - 1)/2 </span>
<span>finally : </span>
<span>S(n) = 4050 * (3^(n+1) - 1) </span>
<span>and this allows you to obtain the month n, if you know S(n) : </span>
<span>3^(n+1) = S(n) /4050 + 1 </span>
<span>therefore : </span>
<span>n = ln[S(n) /4050 + 1] /ln3 - 1 </span>
<span>hope it' ll help !!</span>
