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butalik [34]
3 years ago
15

What is the probability of getting a number greater than or equal to 2 when rolling a number cube number 1 to 6

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
Hello!

The probability of rolling a number that is equal to or greater than 2 is a 5/6 chance. It is a 5/6 chance because there are 6 numbers on a dice and the total amount of numbers from 2 to 6 is 5 numbers (2, 3, 4, 5, 6).

I hope this helps!
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A painter painted about a half a room in a half day. Coley estimated the painter would paint 7 rooms in 7 days. Cole's estimate
DIA [1.3K]
Hello Trickstwin,

How are you doing? Referring to your question, of course, we see that the painter paints half a room in half a day. We want to find the base of this operation. So, we have to figure out how many rooms he paints in one full day. If he paint half a room in half a day, he then must paint a room in one whole day. So we know the following:
\left \{ {{Rooms Painted=1} \atop {Days Taken=1}} \right.

Which leads on. We multiply that one day by seven, and funny enough:

1 x 7 = 7 which means his guess is reasonable. Do you get what I am saying? If so, your answer is True, have a great day!

Thank you,
Darian D. 
3 0
3 years ago
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The scale of a map of Florida is 2 cm = 3 miles. If the distance between Apopka and Orlando on the map is 12 cm what is the actu
babunello [35]

Answer:

18 miles

Step-by-step explanation:

2cm=3 miles

12cm=18 miles

You multiply both sides by 6,

8 0
3 years ago
Simply the expresstion: 5+8 (3 + x )
DIA [1.3K]
The answer is going to be 8x+29
7 0
2 years ago
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-3/8+(-7/8) how solve
Fed [463]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em><em>✌</em>

3 0
4 years ago
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Given that (7x-8)/(2x-1)(x-2) <br><br> Use Partial Fraction Decomposition to Find A and B.
koban [17]

We look for constants <em>a</em> and <em>b</em> such that

\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac a{2x-1} + \frac b{x-2}

Rewrite all terms with a common denominator and set the numerators equal:

\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac{a(x-2)}{(2x-1)(x-2)} + \frac{b(2x-1)}{(x-2)(2x-1)} \\\\ \frac{7x-8}{(2x-1)(x-2)} = \frac{a(x-2)+b(2x-1)}{(2x-1)(x-2)} \\\\ \implies 7x-8 = a(x-2) + b(2x-1) = (a+2b)x - 2a - b

Then

<em>a</em> + 2<em>b</em> = 7

-2<em>a</em> - <em>b</em> = -8

Solve for <em>a</em> and <em>b</em>. Using elimination: multiply the first equation by 2 and add it to the second equation:

2 (<em>a</em> + 2<em>b</em>) + (-2<em>a</em> - <em>b</em>) = 2(7) + (-8)

2<em>a</em> + 4<em>b</em> - 2<em>a</em> - <em>b</em> = 14 - 8

3<em>b</em> = 6

<em>b</em> = 2

Then

<em>a</em> + 2(2) = 7   ==>   <em>a</em> = 3

and so

\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac 3{2x-1} + \frac 2{x-2}

7 0
3 years ago
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