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mariarad [96]
3 years ago
8

How many different ways can the line be named? What are those names?

Mathematics
2 answers:
boyakko [2]3 years ago
5 0

Answer: A. 3 ways: k, DE, ED (both DE and ED have line markers over top)

To name a line, we just need two points on the line. We list them in any order because the line extends forever in both directions. Contrast this with a ray where order does matter. The little k is another way to name a line, potentially simplifying things.

Choice B is close, but it mentions ray DE instead of line DE. Choice C is missing line ED. Choice D is a similar story as choice B. These facts allow us to rule out B through D.

Genrish500 [490]3 years ago
3 0
A should be your answer
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Answer:

C. The temperature was 32 degrees higher when t = 7 than when t = 3

Step-by-step explanation:

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4 0
3 years ago
Cramers rule<br>hurry up plzzz​
olya-2409 [2.1K]

Answer:

Answers provided below

Step-by-step explanation:

From the simultaneous linear equation, we have the coefficient matrix as;

(3 4 5)

(2 -1 8)

(5 -2 7)

The x-matrix is Dx is given by;

(18 4 5)

(13 -1 8)

(20 -2 7)

Similarly, the y-matrix Dy is given by;

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Also,the z-matrix Dz is given by;

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Determinant of the coefficient matrix from online determinant calculator is;

D = 136

Determinant of the x-matrix from online determinant calculator is; Dx = 92

Determinant of the y-matrix from online determinant calculator is; Dy = 696

Determinant of the z-matrix from online determinant calculator is; Dz = 576

From crammers rule;

x = Dx/D = 92/136

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6 0
2 years ago
a traveler has 7 pieces of luggage . how many ways can the traveler select 3 pieces of luggage for a trip
7nadin3 [17]
Well, you could assign a letter to each piece of luggage like so...

A, B, C, D, E, F, G

What you could then do is set it against a table (a configuration table to be precise) with the same letters, and repeat the process again. If the order of these pieces of luggage also has to be taken into account, you'll end up with more configurations.

My answer and workings are below...

35 arrangements without order taken into consideration, because there are 35 ways in which to select 3 objects from the 7 objects.

210 arrangements (35 x 6) when order is taken into consideration.

*There are 6 ways to configure 3 letters.

Alternative way to solve the problem...

Produce Pascal's triangle. If you want to know how many ways in which you can choose 3 objects from 7, select (7 3) in Pascal's triangle which is equal to 35. Now, there are 6 ways in which to configure 3 objects if you are concerned about order.

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3 years ago
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