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Eduardwww [97]
2 years ago
10

Say that the economy is in an expansion, causing wages to increase by six percent. if you previously received a monthly salary o

f $1,375.00, what will your new monthly salary be? round all dollar values to the nearest cent. a. $2,365.00 b. $1,604.17 c. $1,462.77 d. $1,457.50
Mathematics
1 answer:
Westkost [7]2 years ago
8 0

From previously received a monthly salary of $1,375.00, Your new monthly salary increase by six percent would be $1,457.50.

What is the percentage?

A percentage is a minimum number or ratio that is measured by a fraction of 100.

You previously received a monthly salary of $1,375.00

Now by economic expansion, causing wages to increase by 6%

Increment of the salary = 6% of 1,375.00

= 6/100 × 1,375

= 0.06 × 1,375

= $82.50

So, your new monthly salary would be = $1,375.00 + $82.50

                                                               = $1,457.50

Hence, your new monthly salary would be $1,457.50.

Learn more about percentages;

brainly.com/question/13450942

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Answer:
1/2 if it's a probability question of getting one blue pen But there's also very little information on the question
Step-by-step explanation:

4 0
2 years ago
The point P(9, 12) is on the terminal side of θ. Evaluate cos θ.
frutty [35]
<span>P(9,12): For all intents and purposes, the hypotenuse is "r", the opposite side is "y", and the adjacent side is "x".

x = 9 (from the P(9,12))
y = 12 (also from the point)

Using the Pythagorean Theorem, you find out that r = 15.

Therefore, since cos θ = x/r
cos θ = 9/15 or 3/5

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7 0
3 years ago
Please the answer and how i should write it
Agata [3.3K]

Answer:

86,400,000 bacteria

Step-by-step explanation:

2^5=32, 3^3=27, 10^5=100,000

32*27*100,000

5 0
3 years ago
Read 2 more answers
How do I complete these questions a bit confused . (extra credit work )​
otez555 [7]

Answer:

(1)

a = \frac{3\sqrt 3}{2}

b = \frac{3}{2}

(2)

a = \sqrt 6

b = \sqrt 2

Step-by-step explanation:

Solving (1):

Considering

\theta = 60^o

We have:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60^o) = \frac{a}{3}

Solve for a

a = 3 * \sin(60^o)

\sin(60^o) = \frac{\sqrt 3}{2}

So:

a = 3 * \frac{\sqrt 3}{2}

a = \frac{3\sqrt 3}{2}

To solve for b, we make use of Pythagoras theorem

3^2 = a^2 + b^2

This gives

3^2 = (\frac{3\sqrt 3}{2})^2 + b^2

9 = \frac{9*3}{4} + b^2

9 = \frac{27}{4} + b^2

Collect like terms

b^2 = 9 - \frac{27}{4}

Take LCM and solve

b^2 = \frac{36 - 27}{4}

b^2 = \frac{9}{4}

Take square roots

b = \frac{3}{2}

Solving (2):

Considering

\theta = 60^o

We have:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60^o) = \frac{a}{2\sqrt 2}

Solve for a

a = 2\sqrt 2 * \sin(60^o)

\sin(60^o) = \frac{\sqrt 3}{2}

So:

a = 2\sqrt 2 * \frac{\sqrt 3}{2}

a = \sqrt 2 * \sqrt 3

a = \sqrt 6

To solve for b, we make use of Pythagoras theorem

(2\sqrt 2)^2 = a^2 + b^2

This gives

(2\sqrt 2)^2 = (\sqrt 6)^2 + b^2

8 = 6 + b^2

Collect like terms

b^2 = 8 - 6

b^2 = 2

Take square roots

b = \sqrt 2

3 0
3 years ago
Use the Pythagorean theorem to find the third side of the triangle.​
ziro4ka [17]

Answer:

9.2 (1DP)

Step-by-step explanation:

  1. First you do 10^2 which is 10 X 10 = 100
  2. Then you do 4^2 which is 4 X 4 = 16
  3. Then you do 100 - 16. The way Ive learnt it is that if the hypotenuse isn't the one you have to find then minus of it it is then plus. So 100 - 16 = 84
  4. A^2 + B^2 = C^2 84 is C^2 meaning now you have to square root it
  5. Square root of 84 is 9.2 to 1 DP
6 0
3 years ago
Read 2 more answers
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