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IrinaK [193]
4 years ago
15

How long is a rectangular field with a width of 3/5 mile and an area of 21/50 square mile?

Mathematics
2 answers:
Elan Coil [88]4 years ago
4 0
w=\frac{3}{5}mi\\\\l=?\\\\A_{\fbox{ }}=w\times l;\ A_{\fbox{ }}=\frac{21}{50}mi^2\\\\\frac{3}{5}l=\frac{21}{50}\ \ \ \ \ |multiply\ both\ sides\ by\ \frac{5}{3}\\\\l=\frac{21}{50}\times\frac{5}{3}\\\\l=\frac{7}{10}\\\\Answer:\boxed{\frac{7}{10}mi=0.7mi}
KIM [24]4 years ago
4 0
A = B*L

A = 21/50 sq miles
B =  3/5 mile
L = ? mile

L = A/B
L = (21/50)/(3/5)

* dividing by fraction is same as multiplying by it's reciprocal

L = (21/50)*(5/3)
L = (21*5)/(50*3)
L = 105/150

*divide both numerator & denominator by 5

L = 21/30

*divide both numerator & denominator by 3

<u><em>L = 7/10 miles</em></u>


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Dvinal [7]
So to find the value of -3 do the following process:

Insert the -3 in the x’s in the equation on the top of the table

y= 5x -3x to the second power + 3

y= 5 (-3) -3(-3) to the second power + 3

Then continue to simplify the equation

y= -15 + 9 to the second power + 3

y= -15 + 84

y = 69

Y= 69 for the chart for -3

For b, c, and d insert the number in the x values and simplify like the previous equation.

If you are confused, feel free to ask questions. I hope this is effective and helps you in your studies.
4 0
2 years ago
Jake paints all sides except the bottom of the box length=20cm width=15cm height=12
Crazy boy [7]

Answer:

Area Painted = (2*12*15) + (2*20*12)

Step-by-step explanation:

If you imagine a box, you know that the bottom area would be found by multiplying the length by the width. Thus, the only other area you want to find are the sides of the box. I multiplied the length and the height as well as the width and the height. I multiplied that by 3 because there's two sides that are always going to be the same. I recommend you draw a picture before attempting to write an expression,

Hope this helped :)

6 0
4 years ago
Use mathematical induction to prove the statement is true for all positive integers n. 1^2 + 3^2 + 5^2 + ... + (2n-1)^2 = (n(2n-
Charra [1.4K]

Answer:

The statement is true is for any n\in \mathbb{N}.

Step-by-step explanation:

First, we check the identity for n = 1:

(2\cdot 1 - 1)^{2} = \frac{2\cdot (2\cdot 1 - 1)\cdot (2\cdot 1 + 1)}{3}

1 = \frac{1\cdot 1\cdot 3}{3}

1 = 1

The statement is true for n = 1.

Then, we have to check that identity is true for n = k+1, under the assumption that n = k is true:

(1^{2}+2^{2}+3^{2}+...+k^{2}) + [2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}

\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)}{3} +[2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}

\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot [2\cdot (k+1)-1]^{2}}{3} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}

k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot (2\cdot k +1)^{2} = (k+1)\cdot (2\cdot k +1)\cdot (2\cdot k +3)

(2\cdot k +1)\cdot [k\cdot (2\cdot k -1)+3\cdot (2\cdot k +1)] = (k+1) \cdot (2\cdot k +1)\cdot (2\cdot k +3)

k\cdot (2\cdot k - 1)+3\cdot (2\cdot k +1) = (k + 1)\cdot (2\cdot k +3)

2\cdot k^{2}+5\cdot k +3 = (k+1)\cdot (2\cdot k + 3)

(k+1)\cdot (2\cdot k + 3) = (k+1)\cdot (2\cdot k + 3)

Therefore, the statement is true for any n\in \mathbb{N}.

4 0
3 years ago
Which expression is not equivalent to 8 · x · 2 · y?<br><br> 8 x + 2 y<br> 16 xy<br> 16 yx
andriy [413]

The answer is...

8x+2y

4 0
3 years ago
Read 2 more answers
Gonna need help on this too. =/
krek1111 [17]

Answer:

The price for each pound of tuna appears to be the same

Predicted amount of tuna that sells for $40: 10 pounds

Step-by-step explanation:

16/4=4

28/7=4

36/9=4

$4 for 1 pound of tuna.

5 0
3 years ago
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