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3 years ago

How long is a rectangular field with a width of 3/5 mile and an area of 21/50 square mile?

2 answers:

4 0

$w=\frac{3}{5}mi\\\\l=?\\\\A_{\fbox{ }}=w\times l;\ A_{\fbox{ }}=\frac{21}{50}mi^2\\\\\frac{3}{5}l=\frac{21}{50}\ \ \ \ \ |multiply\ both\ sides\ by\ \frac{5}{3}\\\\l=\frac{21}{50}\times\frac{5}{3}\\\\l=\frac{7}{10}\\\\Answer:\boxed{\frac{7}{10}mi=0.7mi}$

KIM [24]3 years ago

4 0

A = B*L

A = 21/50 sq miles
B = 3/5 mile
L = ? mile

L = A/B
L = (21/50)/(3/5)

* dividing by fraction is same as multiplying by it's reciprocal

L = (21/50)*(5/3)
L = (21*5)/(50*3)
L = 105/150

*divide both numerator & denominator by 5

L = 21/30

*divide both numerator & denominator by 3

L = 7/10 miles

You might be interested in

Log10 (2x + 1) - logio(3x - 2) = 1

Pavlova-9 [17]

Answer: x=3/4

Step-by-step explanation:

To solve, first express the left side as one logarithm. To do so, apply the quotient rule which is log_bM/N=log_bM-log_bN .

log((2x+1)/(3x-2))=1

Then, express the equation to its equivalent exponential form to eliminate the logarithm.

Note that the exponential form of log_b M=a is M=b^a .

Since the base of the logarithm in the given equation is not written, it indicates that its base is 10.

So re-writing the equation, it becomes:

log_10((2x+1)/(3x-2))=1

And its exponential form is:

(2x+1)/(3x-2)=10^1

(2x+1)/(3x-2)=10

Now that the equation has no more logarithm, the next step is to remove the x in the denominator.

To do so, multiply both sides by 3x-2.

(3x-2)*(2x+1)/(3x-2)=10*(3x-2)

2x+1=30x-20

Next, combine like terms.

To combine 30x and 2x, bring them together on one side of the equation. So, move 2x to the right side by subtracting both sides by 2x.

2x-2x+1=30x-2x-20

1=28x-20

To combine 20 and 1, bring them together on the side opposite the term with x. So, add both sides by 20.

1+20=28x-20+20

21=28x

And, divide both sides by 28 to have x only at the right side.

21/28=(28x)/28

3/4=x

Hence, the solution to the given equation is x=3/4 .

3 0

3 years ago

The number of a certain company's video stores can be approximated by the linear equation y= -264x+4682, where x is the number o

ahrayia [7]

Answer:

Missing co-ordinate for the ordered pair is $(7,2834)$

Y-intercept is $(0,4682)$

X-intercept is $(17.73,0)$

Step-by-step explanation:

The number of a certain company's video stores can be approximated by the linear equation

$y= -264\ x+4682$

where $y$ is the number of stores and $x$ represents the number of years after 1990.

To find the missing co-ordinate for the ordered pair solution $(7,?)$

For the ordered pair, we are given the $x$ value which is =7 i.e 7 years after 1990. Thus we will plugin $x=7$ in the linear equation to get the $y$ value which is number of stores after 7 years from 1990.

$y= -264\ (7)+4682$

$y= -1848+4682$

$y= 2834$

Thus the ordered pair is $(7,2834)$

To find y-intercept which is the point where the line touches the y-axis, we would plugin $x=0$ in the equation as the x-coordinate is 0 at y-axis.

$y= -264\ (0)+4682$

$y= 0+4682$

$y=4682$

Thus y-intercept is at point $(0,4682)$

To find x-intercept which is the point where the line touches the x-axis, we would plugin $y=0$ in the equation as the y-coordinate is 0 at x-axis and thus for $x$