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IrinaK [193]
3 years ago
15

How long is a rectangular field with a width of 3/5 mile and an area of 21/50 square mile?

Mathematics
2 answers:
Elan Coil [88]3 years ago
4 0
w=\frac{3}{5}mi\\\\l=?\\\\A_{\fbox{ }}=w\times l;\ A_{\fbox{ }}=\frac{21}{50}mi^2\\\\\frac{3}{5}l=\frac{21}{50}\ \ \ \ \ |multiply\ both\ sides\ by\ \frac{5}{3}\\\\l=\frac{21}{50}\times\frac{5}{3}\\\\l=\frac{7}{10}\\\\Answer:\boxed{\frac{7}{10}mi=0.7mi}
KIM [24]3 years ago
4 0
A = B*L

A = 21/50 sq miles
B =  3/5 mile
L = ? mile

L = A/B
L = (21/50)/(3/5)

* dividing by fraction is same as multiplying by it's reciprocal

L = (21/50)*(5/3)
L = (21*5)/(50*3)
L = 105/150

*divide both numerator & denominator by 5

L = 21/30

*divide both numerator & denominator by 3

<u><em>L = 7/10 miles</em></u>


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B (1 , 3) , D (1 , -2)

Step-by-step explanation:

∵ A (-3 , 3) , C (-3 , -2)

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∵ The area of the rectangle = 20

∴ The width of it = 20 ÷ 5 = 4

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∵ y-coordinate = 3 - 5 = -2

∴ D (1 , -2)

3 0
3 years ago
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Step-by-step explanation:

Given: The ratio of cranberries and raspberries is 8:9 .

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6 0
2 years ago
Given the points (-4,8)and(6,-12)
MissTica

Answer:

1.

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2.

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