F(x)= 3x + 1
f(x)= 3(3) + 1
= 9 + 1
= 10
g(x)= 4x - 5
= 4(3) - 5
= 12 - 5
= 7
So... A. f(x) is greater when x=3
Answer:
?
Step-by-step explanation:
Answer:
x=1
Step-by-step explanation:
check the attatched photo please
The correct answer is shown in attached figure
To find the correct graph, we should study the continuity of the function
Check the continuity at x = -2
from the left ⇒⇒ f(-2) = 1/2 * -2 + 3 = 2
from the right ⇒⇒ f(-2) = 2
∴ The function is continuous at x = -2
Check the continuity at x = 3
from the left ⇒⇒ f(3) = 2
from the right ⇒⇒ f(3) = 2*3 - 3 = 3
∴ The function is jump discontinuous at x = 3
From the previous results the correct graph is the last as shown in attached graph.
Function A:

. Vertical asymptotes are in the form x=, and they are a vertical line that the function approaches but never hits. They can be easily found by looking for values of <em>x</em> that can not be graphed. In this case, <em>x</em> cannot equal 0, as we cannot divide by 0. Therefore <em>x</em>=0 is a vertical asymptote for this function. The horizontal asymptote is in the form <em>y</em>=, and is a horizontal line that the function approaches but never hits. It can be found by finding the limit of the function. In this case, as <em>x</em> increases, 1/<em>x</em> gets closer and closer to 0. As that part of the function gets closer to 0, the overall function gets closer to 0+4 or 4. Thus y=4 would be the horizontal asymptote for function A.
Function B: From the graph we can see that the function approaches the line x=2 but never hits. This is the vertical asymptote. We can also see from the graph that the function approaches the line x=1 but never hits. This is the horizontal asymptote.