The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Answer:
<u>193.2 cm²</u>
Step-by-step explanation:
Area = 5.2 x 6 + 3 x 6 x 9
= 31.2 + 162
= <u>193.2 cm²</u>
Answer:
Step-by-step explanation:
To write this sentence as equation
We get
r×338+97=r
338r+97=r
To solve further
r-338r=97
-337r=97
r=-0.2878
