Question

Solve for the variable in the following equation: 1 / 6c + 1 / 3 = - 2

Answer 1

Answer:

C. c = −14

Step-by-step explanation:

Combine multiplied terms into a single fraction

$\frac{1}{6} c+\frac{1}{3} = - 2$

$\frac{1c}{6} +\frac{1}{3} =-2$

Multiply by 1

$\frac{1c}{6} +\frac{1}{3} =-2$

$\frac{c}{6} +\frac{1}{3} =-2$

Subtract $\frac{1}{3}$ from both sides of the equation

$\frac{c}{6} +\frac{1}{3} =-2$

$\frac{c}{6} +\frac{1}{3} -\frac{1}{3} =-2-\frac{1}{3}$

Subtract the numbers

$\frac{c}{6} +\frac{1}{3} -\frac{1}{3} =-2-\frac{1}{3}$

$\frac{c}{6} =-2-\frac{1}{3}$

Subtract the numbers

$\frac{c}{6} =-2-\frac{1}{3}$

$\frac{c}{6} =-\frac{7}{3}$

Multiply all terms by the same value to eliminate fraction denominators

$\frac{c}{6} =-\frac{7}{3}$

$c \frac{c}{6} =6(-\frac{7}{3} )$

Cancel multiplied terms that are in the denominator

$c \frac{c}{6} =6(-\frac{7}{3} )$

c = 6 $(-\frac{7}{3} )$

Multiply the numbers

c = 6 $(-\frac{7}{3} )$

c = - 14

Answer 2

Answer: C. C=-14

Step-by-step explanation:

Given

(1/6)c+1/3=-2

Multiply both sides by the LCM of 1/6 and 1/3(Least Common Multiple)

6[(1/6)c+1/3]=(-2)(6)

c+2=-12

Subtract 2 on both sides

c+2-2=-12-2

c=-14

Hope this helps!! :)

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