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2 years ago

What is the recursive formula for the geometric sequence ? 6,-24,96,-384,...

Mathematics

1 answer:

irinina [24]2 years ago

5 0

Answer:

$the \: recursive \: formula \: is \\ tn = 6( {4}^{n - 1} )$

Answer is given below with explanations.

Step-by-step explanation:

$the \: given \: geometric \: sequence \: is \\ 6, \: - 24, \: 96, \: - 384 \\ the \: first \: term \: is \: 6 \: and \: the \: common \: ratio \: is \: - 4 \\ the \: {n}^{th} term \: of \: the \: geometric \: sequence \: is \\ tn = a {r}^{n - 1} \\ here \: first \: term \:( a) = 6 \\ common \: ratio \: (r) = - 4 \\ on \: substituting \: the \: values \: in \: formula \\ tn = 6( { - 4}^{n - 1} ) \\ the \: above \: mentioned \: formula \: is \: \\ the \: recursive \: formula \: \\ for \: geometric \: sequence.$

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Lady bird [3.3K]

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3 years ago

The perimeter of this triangle is 25 units. An angle bisector divides one side of the triangle into lengths of 2 and 3. Find the

grin007 [14]

Answer:

8 and 12

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Sides on one side of the angle bisector are proportional to those on the other side. In the attached figure, that means

AC/AB = CD/BD = 2/3

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25 = AB + BC + AC

25 = AB + 5 + (2/3)AB . . . . . . substituting AC = 2/3·AB. BC = 2+3 = 5.

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Alternate solution

The sum of ratio units is 2+3 = 5, so each one must stand for 25/5 = 5 units of length.

That is, the total of lengths on one side of the angle bisector (AC+CD) is 2·5 = 10 units, and the total of lengths on the other side (AB+BD) is 3·5 = 15 units. Since 2 of the 10 units are in the segment being divided (CD), the other 8 must be in that side of the triangle (AC).

Likewise, 3 of the 15 units are in the segment being divided (BD), so the other 12 units are in that side of the triangle (AB).

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3 years ago

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<h3>How to determine the probability?</h3>

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Hence, the probability that she picks two white socks is 0.0357

Read more about probability at:

brainly.com/question/251701

#SPJ1

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