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ale4655 [162]
4 years ago
10

it takes a smaller hose twice as long to fill a small pool as it does a larger hose. it takes both hoses working together 40 min

utes to fill the pool. how long will it take the smaller hose to fill the pool by itself?
Mathematics
1 answer:
Lynna [10]4 years ago
7 0
Lets denote the hoses as variables.
small hose per unit time = h
larger hose per unit time = H

h = 1/2H

40(h+H) = full
40(h+2h) = full
40(3h) = full
120(h) = full

120 minutes or 2 hours
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Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relation between angle, adjacent side, and hypotenuse:

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Step-by-step explanation:


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maks197457 [2]

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Step-by-step explanation:

1. Multiply

(5.68^3 × 8.14= 1491.65851648)

94100 × √38.2 / 1491.65851648

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<u>3</u><u>.</u><u> </u><u> </u><u>multiply </u>

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(581595.85796324 / 1491.65851648 = 389.89879489)

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The cost for Tia and her five friends to be admitted to ice skate and eat is 60$, and the equation to calculate this is C = 2(5p).

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