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3 years ago

Find the vertex of this parabola y=-5x^2-10x-15

Mathematics

2 answers:

Fynjy0 [20]3 years ago

7 0

Answer:(-1,-10)

Step-by-step explanation:

natta225 [31]3 years ago

3 0

Answer:

vertex = (- 1, - 10 )

Step-by-step explanation:

given the equation of a parabola in standard form

y = ax² + bx + c : a ≠ 0

Then the x-coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

y = - 5x² - 10x - 15 is in standard form

with a = - 5, b = - 10 and c = - 15, hence

$x_{vertex}$ = - $\frac{-10}{-10}$ = - 1

substitute x = - 1 into the equation for y

y = - 5(- 1)² - 10(- 1) - 15 = - 5 + 10 - 15 = - 10

vertex = (- 1, - 10 )

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