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Oxana [17]
2 years ago
12

How are <4 and <5 related?

Mathematics
1 answer:
Inessa [10]2 years ago
7 0
They are supplementary angles since they lay on a line, which makes them a linear pair, meaning that any linear pair equals 180°
I hope this helps.
YOU'RE WELCOME :D
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Jewan is setting up a monthly budget. His gross monthly income is $3125, but 20% is deducted for taxes. How much money is deduct
romanna [79]

Answer:

$625

$2500

Step-by-step explanation:

tax = percent of tax x income

0.2 x 3125 = 625

amount remaining = income - tax

3125 - 625

4 0
2 years ago
A biologist determined that there were 42 oak trees in a 5-acre forest. How many oak trees would be expected on 40 acres of iden
klio [65]

Answer:

336

Step-by-step explanation:

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2 years ago
Anyone good at maths who can help me? <br> brainiest will be given, THANK YOU!!!
pentagon [3]

Answer:

a) £338.64     b) 21.73kg     c) 334.65m

Step-by-step explanation:

on calculator type:

408x83%

53x41%

345x97%

4 0
3 years ago
Read 2 more answers
8 classmates share 4 pizzas each person receive 4 eights right<br> ...?
Jet001 [13]
For the given question above, if you divide the 4 pizzas up between the 8 people you get the fraction 4/8. So this is TRUE.
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6 0
3 years ago
a team of 10 players is to be selected from a class of 6 girls and 7 boys. match each scenario to its probability
mars1129 [50]

Step-by-step explanation:

The selection of r objects out of n is done in

many ways.

The total number of selections 10 that we can make from 6+7=13 students is  

thus, the sample space of the experiment is 286

A.  

"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

P(all 6 girls chosen)=35/286=0.12

B.

"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is  

so the probability is 20/286=0.07

C.

"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.  

the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.

"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in  

many ways,

so the probability is 126/286=0.44

Did this help??

8 0
2 years ago
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