Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
The answer is B because 7 does not evenly fit into 71 so the first box is 10 and the second box is .14285714285714or is simplified.143 or .14
Answer: 
Step-by-step explanation:
The difference is obtained by subtracting the polynomial
and the polynomial
.
It is important to remember the multiplication of signs:

Then, you can subtract both polynomials to find the difference.
You need to Distribute the negative sign:

Finally, you have to add the like terms. Then:

Answer:
4
Step-by-step explanation:
terrible, but it could be worse
Answer:

Step-by-step explanation:
Hi!
The options regarding the inequalities are not listed, though we can still proceed to write the inequality.
From the problem statement you cannot spend more than $50
and you are charged admission fee of $6 flat
a ride cost $2.50 per ride
the number of rides is given as r
yet in all you must not go beyond your limit
Therefore the inequalities can be presented as
