You first need to change 2 1/3 into a mixed fraction, which would be 7/3 and multiply by 5/1, which would be 35/3, and then divide 35 and 3 to get and answer of 11 2/3, which is the answer.
Answer:
21 and 26 totaling 47sticks
Step-by-step explanation:
Th number of sticks form an arithmetic progression
1, 6, 11, 16...
The nth term of an arithmetic progression is expressed as;
Tn = a+(n-1)d
a is the first term = 1
d is the common difference
d = 6-1 = 11-6 = 5
n is the number of terms
The next two terms are the fifth and sixth term
T5 = 1+(5-1)5
T5 = 1+4(5)
T5 = 1+20
T5 = 21
T6 = 1+(6-1)5
T6 = 1+5(5)
T6 = 1+25
T6 = 26
Hence the number of sticks needed in the next two piles are 21 and 26 totaling 47sticks
Answer:
87.5 by 70 inches
Step-by-step explanation:
No options were given. So, I will calculate the minimum width
Given
Height = 70 in ---- of the printed logo
Required
Determine the dimension that keeps the requirement
Let x be the width of the printed logo.
So, the ratio can be represented as:
Equate both ratios
As fraction
Multiply through by 70
So, one of the dimension that meets the requirement is a width of 87.5 inches
Answer:
yes because....
Step-by-step explanation:
6 + 11 > 13
