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Alborosie
3 years ago
9

SOMEONE PLEASE HELP ME ASAP PLEASE!!!​

Mathematics
1 answer:
Sergio [31]3 years ago
3 0

Answer:

y = x - 5

Step-by-step explanation:

The equation given to us is;

y = x - 3

y = (1)x + (-3)

y = mx + c

Where m = slope of the line = 1

As parallel line have same slope, slope of second line is also 1

Use general equation to find line

y = mx + c

y = 1x + c

y = x + c

Substitute (3,-2) in the given equation:

-2 = 3 + c

c = -5

Substitute m=1 and c=-5 in general equation to find the equation of line:

y = mx + c

y = x - 5

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You can tell if a graph is a function by the x and y value if you find the x and y values, the x cannot repeat for the graph to be a function.
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4 years ago
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Find the area of the polygon with the given vertices. N(-2,1), P(3,1), Q(3, -1), R(-2, -1)
Novay_Z [31]

Answer:

10

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see attached

6 0
3 years ago
Which function below is the inverse of f(x)=x^2-25
ivanzaharov [21]

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y = x^2-25

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4 0
3 years ago
Can someone help me solve this differentiation/tangent problem?
nirvana33 [79]
A)

\bf g'(x)=\stackrel{product~rule}{2x\cdot f(x)+x^2\cdot  f'(x)}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
g'(5)=2(5)\cdot f(5)+(5)^2\cdot f'(5)\implies g'(5)=50+500\\\\\\ g'(5)=550\\\\
-------------------------------\\\\
g(5)=(5)^2f(5)\implies g(5)=125
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}
\begin{cases}
x=5\\
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\end{cases}\implies y-125=550(x-5)
\\\\\\
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b)

\bf h'(x)=\stackrel{quotient~rule}{\cfrac{f'(x)(x-6)~~-~~f(x)\cdot 1}{(x-6)^2}}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
h'(5)=\cfrac{f'(5)(5-6)~~-~~f(5)\cdot 1}{(5-6)^2}
\\\\\\
h'(5)=\cfrac{5(-1)-5}{(-1)^2}\implies h'(5)=-10\\\\
-------------------------------\\\\

\bf h(5)=\cfrac{f(5)}{5-6}\implies h(5)=\cfrac{5}{-1}\implies h(5)=-5
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\quad 
\begin{cases}
x=5\\
y=-5\\
\stackrel{m}{-10}
\end{cases}\implies y-(-5)=-10(x-5)
\\\\\\
y+5=-10x+50\implies y=-10x+45
3 0
4 years ago
Write 4.39 as a mixed number in simplest form. The decimal .39 is repeating. I don’t know how to type the solid line over the .3
Sveta_85 [38]

Answer:

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Step-by-step explanation

If a decimal is repeating, then the fraction would be the repeating number (in this case, 39) over the largest "nine number." If the repeating decimal was only .3 repeating then the fraction would be 3/9. If the fraction was .789 repeating, then the fraction would be 784/999. My teacher used to call this the "nine rule" but that isn't the actual name, so don't call it that. It is a nice way of remembering it though. Also, don't forget the whole number. because the .39 is repeating, that would be 39/99 as a fraction and then the whole number 4 in front of it - 4 39/99. also don't forget to simplify the fraction when you can. In this case, you can simplify 39/99 into 13/33 so the correct answer is 4 13/33.

8 0
3 years ago
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