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3 years ago

SOMEONE PLEASE HELP ME ASAP PLEASE!!!

Mathematics

1 answer:

Sergio [31]3 years ago

3 0

Answer:

y = x - 5

Step-by-step explanation:

The equation given to us is;

y = x - 3

y = (1)x + (-3)

y = mx + c

Where m = slope of the line = 1

As parallel line have same slope, slope of second line is also 1

Use general equation to find line

y = mx + c

y = 1x + c

y = x + c

Substitute (3,-2) in the given equation:

-2 = 3 + c

c = -5

Substitute m=1 and c=-5 in general equation to find the equation of line:

y = mx + c

y = x - 5

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I need help on c plz

Triss [41]

Pls write out the question it is not clear

8 0

3 years ago

Read 2 more answers

In the diagram, WZ=StartRoot 26 EndRoot.

gogolik [260]

Answer:

$P = 8 + 2\sqrt{26}$

Step-by-step explanation:

Given

$W = (-2, 4)$

$X = (2, 4)$

$Y = (1, -1)$

$Z = (-3,-1)$

Required

The perimeter

First, calculate the distance between each point using:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 -y_2)^2$

So, we have:

$WX = \sqrt{(-2- 2)^2 + (4-4)^2 } =4$

$XY = \sqrt{(2- 1)^2 + (4--1)^2 } =\sqrt{26}$

$YZ = \sqrt{(1- -3)^2 + (-1--1)^2 } =4$

$ZW = \sqrt{(-3--2)^2 + (-1-4)^2 } =\sqrt{26}$

So, the perimeter (P) is:

$P = 4 + \sqrt{26} + 4 + \sqrt{26}$

$P = 8 + 2\sqrt{26}$

8 0

3 years ago

the line joining A(a, 3) to B(2 -3) is perpendicular to the line joining C(10,1) to B. The value of a is?

RideAnS [48]

Well, first off, let's find what is the slope of BC

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
B&({{ 2}}\quad ,&{{ -3}})\quad 
% (c,d)
C&({{ 10}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-(-3)}{10-2}\implies \cfrac{1+3}{10-2}
\\\\\\
\cfrac{4}{8}\implies \cfrac{1}{2}$

now, a line perpendicular to that one, will have a negative reciprocal slope, thus

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{1}{2}\\\\
slope=\cfrac{1}{{{ 2}}}\qquad negative\implies -\cfrac{1}{{{ 2}}}\qquad reciprocal\implies - \cfrac{{{ 2}}}{1}\implies \boxed{-2}$

now, we know the slope "m" of AB is -2 then, thus

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ a}}\quad ,&{{ 3}})\quad 
% (c,d)
B&({{ 2}}\quad ,&{{ -3}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-3-3}{2-a}=\boxed{-2}
\\\\\\
\cfrac{-6}{2-a}=-2\implies -6=-4+2a\implies -2=2a\implies \cfrac{-2}{2}=a
\\\\\\
-1=a$

6 0

3 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

11Alexandr11 [23.1K]

Answer:

Oakdale

Step-by-step explanation:

The median can be seen inside the rectangle in the box-and whisker plot. It is the point in the middle, cutting the rectangle in two. Looking at the plots, Oakdale has a lower median.

4 0

3 years ago

4y+2x=180 solve for x and y

kirill [66]

There you go!! Hope it helps

5 0

3 years ago

SOMEONE PLEASE HELP ME ASAP PLEASE!!!​

SOMEONE PLEASE HELP ME ASAP PLEASE!!!