I got 75582.
Explanation:
First, group the 40 identical candies into 20 pairs. It doesn't matter how since the candies are identical. This grouping will ensure that any assigment will contain at least two candies.
Then think of the 20 groups a 20 beads on a string. We are looking to place 11 separators between them to obtain 12 segments, each with a varying number of beads between them. How many ways are there to place 11 separators to 19 potential spaces between beads? The asnwer is 
Answer:
1. C) 3
2. D) -1
3. D) 7^2 - 8*2 - 16
4. B) 75
5. B) 6^2 + (2 - 8)*sqrt(81)
Step-by-step explanation:
1. (10 - (6-4)^2)/2
= (10 - 2^2)/2
= (10 - 4)/2
= 6/2
= 3
2. PEMDAS states that Multiplication is before Subtraction
8 - (5^2-7)/2
= 8 - (25-7)/2
= 8 - 18/2
= 8 - 9
= -1
3. D) 7^2 - (8*2) - 16
= 49 - 16 - 16
= 49 - 32
= 17
4. 3(2 + 3)^2
= 3(5)^2
= 3(25)
= 75
5. 6^2 + (2 - 8)*sqrt(81)
= 36 + (-6*9)
= 36 - 54
= -18
Answer:
Third side = 8.34 cm
Step-by-step explanation:
Given that,
The perimeter of a triangle, P = 22 cm
One side of a triangle, b = 9 cm
The area of the triangle, A = 20.976 cm²
The formula for the area of a triangle is given by :
Perimeter = Sum of all sides
9 cm + 4.66 cm + x = 22
x = 22 - 13.66
x = 8.34 cm
So, the third side of the triangle is 8.34 cm.
The slope formula is y2-y1/ x2-x1 so after plugging it in it would be 2-3/5-4 and you will get your answer.
Answer:
I think the answer might be D. 2x+4x=150
Step-by-step explanation:
Hope this helps!
