If you draw the circle and divide into 4 quadrants, you can see that the sine is negative, since the quadrant is situated in the negative part of YY', and that the cosine is positive, since the quadrant is situated in the positive part of XX'.
And
, and negative divided by positive gives a negative answer, which means that the tangent is negative on the quadrant IV.
Hope this helps :)
Answer:
Step-by-step explanation:
Where is the question?
9514 1404 393
Answer:
5x -y = -37
Step-by-step explanation:
One way to find the coefficients A and B is to use the differences of the x- and y-coordinates:
A = Δy = y2 -y1 = 2 -(-3) = 5
B = -Δx = -(x2 -x1) = -(-7 -(-8)) = -1
Then the constant C can be found using either point.
5x -y = 5(-7) -2 = -37
The equation of the line is ...
5x -y = -37
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<em>Additional comment</em>
This approach comes from the fact that the slope of a line is the same everywhere.
The "standard form" requires that A be positive, so we chose point 1 and point 2 to make sure that was the case.
Answer:
A
Step-by-step explanation:
Answer:
Domain: [-5, 1)
Range: (5, 1]
General Formulas and Concepts:
<u>Algebra I</u>
- Domain is the set of x-values that can be inputted into function f(x)
- Range is the set of y-values that are outputted by function f(x)
Step-by-step explanation:
According to the graph, our x-values span from -5 to 1. Since -5 is a closed dot, it is inclusive in the domain. Since -1 is an open dot, it is exclusive in the domain:
[-5, 1)
According to the graph, our x-values span from -5 to 1. Since -5 is an open dot, it is exclusive in the range. Since 1 is a closed dot dot, it is exclusive in the range:
(5, 1]
