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Serga [27]
2 years ago
7

What is 1/9 as a percent rounded to the nearest hundredth

Mathematics
1 answer:
lesantik [10]2 years ago
3 0

<h2>, Reffer the attachment </h2>

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View the lane below and calculate the slope<br> by using the slope formula
velikii [3]

Answer:

slope = 4

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (3, 12) ← 2 points on the line

m = \frac{12-0}{3-0} = \frac{12}{3} = 4

6 0
2 years ago
Read 2 more answers
What is the factorization of the polynomial below?<br> 9x2 - 16
Agata [3.3K]

use (a-b) (a+b )

(3x+4) (3x- 4)

8 0
2 years ago
Read 2 more answers
I have a math question
Elena L [17]

For the first question; we have a problem dealing with translations. Our goal is to translate the word problem into an algebraic one. So our numbers are 60, 2, and 5. Our variable, or the letter holding the unknown number's place value,  is N. <span>

</span>The problem states that 60 is MORE THAN the PRODUCT of 5 and N. Focus on the words I bolded and capitalized. These are your key words that tells you what operations you need to use. Note that 'product' signals the operation of multiplication (Since the answer you get from multiplying numbers is called the 'product'.) and 'more than' signals the operation of addition (Because you are left off with more than you originally had before adding). <span>

</span>Now that we know that our algebraic expression contains multiplication, addition, letter N and the numbers 2 and 5; we can start plugging the numbers in.<span>

</span>60 = 2 (more than) + (product of) 5N. The answer for the first attachment is B. <span>

</span>_____________________________________________________________<span>

</span>All we need to do for the AB problem (Question 25 on your material) is solve AB.<span>

</span>Note 1: When a problem has no operation separating two letters or numbers, this means multiplication.<span>

</span>Note 2: A and B are variables. Variables are letters that stand for and hold the place of our unknown quantities. However, the values are not unknown anymore given the fact that the question tells us that A= 42 and B = 2. Thus we substitute A with 42 and B with 2, then work from there. 42 * 2 =84. Answer = A.

____________________________________________________________________

And finally, for question 26, we use PEMDAS. P = parenthesis (), E = exponent x^2, M/D = x or /, A/S means + or subtraction.

According to PEMDAS, we first solve what's parenthesis, which is 77 – 32. Using mental math, 77 – 32 = 45. ( 7 – 3 = 4 and 7 – 2 = 5.). 5/9 * 45 is what we have left. 5 divided by 9 =0.5555555555555556. 0.5555555555555556 * 45 = 25. Answer is D. 

6 0
2 years ago
Suppose that for a randomly selected high school student who has taken a college entrance exam, the probability of scoring above
Sophie [7]

Answer:

3.0

Step-by-step explanation:

n=10

p=0.30

mean=np=10X0.3 = 3

That is it.

5 0
3 years ago
2^5×8^4/16=2^5×(2^a)4/2^4=2^5×2^b/2^4=2^c<br>A=<br>B=<br>C= <br>Please I'm gonna fail math
aleksley [76]

9514 1404 393

Answer:

  a = 3, b = 12, c = 13

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

___

You seem to have ...

  \dfrac{2^5\times8^4}{16}=\dfrac{2^5\times(2^3)^4}{2^4}\qquad (a=3)\\\\=\dfrac{2^5\times2^{3\cdot4}}{2^4}=\dfrac{2^5\times2^{12}}{2^4}\qquad (b=12)\\\\=2^{5+12-4}=2^{13}\qquad(c=13)

_____

<em>Additional comment</em>

I find it easy to remember the rules of exponents by remembering that <em>an exponent signifies repeated multiplication</em>. It tells you how many times the base is a factor in the product.

  2\cdot2\cdot2 = 2^3\qquad\text{2 is a factor 3 times}

Multiplication increases the number of times the base is a factor.

  (2\cdot2\cdot2)\times(2\cdot2)=(2\cdot2\cdot2\cdot2\cdot2)\\\\2^3\times2^2=2^{3+2}=2^5

Similarly, division cancels factors from numerator and denominator, so decreases the number of times the base is a factor.

  \dfrac{(2\cdot2\cdot2)}{(2\cdot2)}=2\\\\\dfrac{2^3}{2^2}=2^{3-2}=2^1

5 0
2 years ago
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