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2 years ago

6 2 need help on this asap

Mathematics

2 answers:

Dahasolnce [82]2 years ago

8 0

Answer:

if its 6² it means 6×6 =36

Alenkasestr [34]2 years ago

5 0

Answer:

Step-by-step explanation:

6² = 6 × 6 = 36

Note any number squared, raised to the power of 2 is the number multiplied by itself.

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A female gorilla weighs 68 kg. How much does she weigh in g.

Alenkasestr [34]

She weighs 68000 grams.

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2 years ago

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Given that secant theta = Negative StartFraction 37 Over 12 EndFraction, what is the value of cotangent theta, for StartFraction

Iteru [2.4K]

$cot\theta$ $=\frac{12}{35}$

Step-by-step explanation:

$sec\theta =\frac{37}{12}$

⇔ $\frac{1}{cos \theta} =\frac{37}{12}$

⇔ $cos \theta = \frac{12}{37}$

we know that

$sin \theta = \sqrt{1-cos^2\theta}$

$sin\theta =\sqrt{1-(\frac{12}{37})^2 }$

$sin\theta=\sqrt{\frac{1225}{1369} }$

$sin\theta = \frac{35}{37}$

Therefore $cot\theta =\frac{cos\theta}{sin\theta}$ $=\frac{\frac{12}{37} }{\frac{35}{37} }$ $=\frac{12}{35}$ , for $\frac{\pi}{2}$

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3 years ago

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A baseball team plays in a stadium that holds 62000 spectators. With the ticket price at $11, the average attendance has been 27

sasho [114]

Answer:

$15.625

Step-by-step explanation:

Let the revenue collected be R and price per spectator be p then the number of spectators be N. Therefore

R=Np

Using equation of slope of y=mx +c where m is gradient and c is y-intercept

When p=$11, N=27000 and when p=$8, N=31000

The gradient, m will be

$m=\frac {31000-27000}{8-11}= -1333.33$

To get the y-intercept

N=-1333.33p+c

When spectator number n is 27000, the price p is $11

27000=-1333.33(11)+c hence we solve c

c=27000+(11*1333.33)= 41666.67

Therefore, the linear equation is

N=-1333.33p+ 41666.67

Substituting the linear equation into R=Np we obtain

R=p(-1333.33p+41666.67)

$R=-1333.33p^{2}+41666.67p$

To obtain maximum revenue, we differentiate the above with respect to price hence obtain

0=2*-1333.33p+41666.67

$p=-\frac {41666.67}{2(-1333.33)}= 15.625$

Therefore, the price that maximizes revenue is $15.625

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The answer is 160.00.

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