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Pie
3 years ago
5

How many positive integer factors of 100 are multiples of 2 or 3?

Mathematics
1 answer:
DedPeter [7]3 years ago
7 0
<h3>Answer:</h3>
  • 6
<h3>Explanation:</h3>

The prime factorization of 100 is ...

... 100 = 2²×5²

The exponents of these factors are 2 and 2. Adding 1 to each of them and finding the product of those sums, we have ...

... (2+1)×(2+1) = 9

The number of divisors of 100 is 9. They are ...

... 1, 2, 4, 5, 10, 20, 25, 50, 100

Of these, 2, 4, 10, 20, 50, 100 are divisible by 2. That is, 6 factors of 100 are multiples of 2.

There are no multiples of 3 that are factors of 100, since 3 is not one of the prime factors.

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Answer:

I think number 2 is the answer, but 4 could be the answer.

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2 years ago
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Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o
GREYUIT [131]

Answer:

And then we can conclude that the middle 75% values of her lap times are from a=126.835 to b=132.585

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the times of a population, and for this case we know the distribution for X is given by:

X \sim N(129.71,2.5)  

Where \mu=129.71 and \sigma=2.5

Since we want the middle 75% values then on tha tails we need 1-0.75 =0.25 or 25% of the data and since the distribution is symmetric we need 12.5 % of the values on each tail.

For this part we want to find a value a and b, such that we satisfy this condition:

P(X>b)=0.125   (a)

P(X   (b)

We can use the z score formula in order to find the value a and b given by:

z=\frac{x-\mu}{\sigma}  

As we can see on the figure attached the z value that satisfy the condition (b) with 0.125 of the area on the left and 0.875 of the area on the right it's z=-1.15. On this case P(Z<-1.15)=0.125 and P(z>-1.15)=0.875

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.15

And if we solve for a we got

a=129.71 -1.15*2.5=126.835

So the value of height that separates the bottom 12.5% of data from the top 87.5% is 126.835.

As we can see on the figure attached the z value that satisfy the condition (b) with 0.875 of the area on the left and 0.125 of the area on the right it's z=1.15. On this case P(Z<1.15)=0.875 and P(Z>1.15)=0.125  

If we use condition (b) from previous we have this:

P(X>b)=P(\frac{X-\mu}{\sigma}>\frac{b-\mu}{\sigma})=0.125  

P(Z>\frac{b-\mu}{\sigma})=0.125

But we know which value of z satisfy the previous equation so then we can do this:

Z=1.15>\frac{b-129.71}{2.5}

And if we solve for a we got

b=129.71 +1.15*2.5=132.585

And then we can conclude that the middle 75% values of her lap times are from a=126.835 to b=132.585

Download pdf
3 0
3 years ago
Mary and dan went to a bookstore. mary bought 2 notebooks and 3 pens for $14.50. dan bought 1 notebook and 2 pens for $7.50. how
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Let n,p be the cost, respectively, of a notebook and a pen. If you buy 2 notebooks and 3 pens (which we know is a cost of $14.50), you spend 2n+3p

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These two equations form the following system:

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Multiply the second equation by 2:

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Subtract the first equation from the second:

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n+2p=7.5 \iff n+2\cdot 0.5=7.5\iff n+1 = 7.5 \iff n=6.5

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