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sdas [7]
3 years ago
7

-9b-6=-3b +48 Step by step

Mathematics
2 answers:
Travka [436]3 years ago
7 0

Answer:

b = -9

Step-by-step explanation:

1. Move the variables to the left side. Be sure to change the terms (add/subtract)

-9b-6 = -3b+48

-9b+3b-6 = 48

2. Combine like terms.

-9b+3b-6 = 48

-6b = 48 + 6

3. Divide both sides by -6.

-6b = 54

b = -9

Juli2301 [7.4K]3 years ago
6 0

Answer:

b=-9

Step-by-step explanation:

Given Equation:

-9b-6=-3b +48

Taking the terms of variable 'b' to one side and the constants to the other side:

Adding '3b' both the sides:

-9b+3b-6=-3b+3b +48\\\\-6b-6=48

Adding '6' both the sides:

-6b-6+6=48+6\\\\-6b=54

Dividing by '-6' both the sides:

b=\dfrac{54}{-6}\\\\ b=-9

The solution of the equation is :  b=-9

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3 years ago
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Answer:

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Step-by-step explanation:

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Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

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In this question:

Fleet of 17 means that N = 17

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What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X > 1) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

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P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

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