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3 years ago

6

If a bag contains 12 apples, 4 bananas, and 8 oranges, what is the part-to-whole ratio of oranges to all fruit?

1 answer:

raketka [301]3 years ago

7 0

Step-by-step explanation:

( 12 : 4 : 8 ) ÷ 24 = 1/2 : 1:6 : 1/3

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What is the measure of the exterior angle, 2?

Alenkasestr [34]

Step-by-step explanation:

<h3>An exterior angle is equal to the addition of two angles not right next to it. The two exterior angles at each vertex are = in measure because they are vertical angles.</h3>

6 0

3 years ago

Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

6 0

3 years ago

Read 2 more answers

Can someone help me with these questions plz

larisa [96]

I need more imformation

7 0

2 years ago

A teacher is giving her students a lesson on inequalities and asks the class to suggest points that are included in the solution

Slav-nsk [51]

Neither of the students are correct

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3 years ago

Which of the following is a solution of x2 + 2x + 4?

RideAnS [48]

Answer:

option-D

Step-by-step explanation:

we are given

$x^2+2x+4$

Let's assume it is equal to 0

$x^2+2x+4=0$

We can use quadratic formula

Suppose, we are given quadratic equations as

$ax^2+bx+c=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

we can compare and find a,b and c

a=1 , b=2 , c=4

now, we can plug values

and we get

$x=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:4}}{2\cdot \:1}$

now, we can simplify it

and we get

$x=-1+\sqrt{3}i,\:x=-1-\sqrt{3}i$

6 0

3 years ago

Read 2 more answers