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Simora [160]
3 years ago
7

38. Solve the simultaneous equations3x + 4y = 11, x + 6y = 13.​

Mathematics
2 answers:
Savatey [412]3 years ago
7 0

Answer:

x=13/7  y=19/14

Step-by-step explanation:

vitfil [10]3 years ago
6 0

Answer:

<h2>X=1</h2><h2>y=2</h2>

please see the attached picture for full solution..

hope this helps...

Good luck on your assignment..

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-5,8 and 2,-6 what the slope
Degger [83]

Answer:

bederr

Step-by-step explanation:

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i got 5 points mfor free haha!!

7 0
3 years ago
You are standing at point p use the drop down menus to identify the path you must follow to get to the gardens
aniked [119]

Answer:

3 blocks east

5 blocks south

Step-by-step explanation:

Hope it helps

5 0
2 years ago
Help, i know the answer but i don’t know how to do the work
Diano4ka-milaya [45]

Answer:

C

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying each radical before combining them.

\sqrt{45t}

= \sqrt{9(5t)}

= \sqrt{9} × \sqrt{5t} = 3\sqrt{5t}

-----------------------------------------------------------------------------

\sqrt{125t}

= \sqrt{25(5t)}

= \sqrt{25} × \sqrt{5t} = 5\sqrt{5t}

---------------------------------------------------------------------------

Hence

2(3\sqrt{5t}) - 3(5\sqrt{5t}

= 6\sqrt{5t} - 15\sqrt{5t}

= - 9\sqrt{5t} → C

7 0
3 years ago
Complete the two-column proof by providing a reason for each of the five statements.
koban [17]

I will only be writing the reasons for each and you can respond if you need clarification for anything:

1. given

2. opposite sides of a parallelogram are congruent (and a rectangle is a parallelogram so the properties apply)

3. def rectangle

4. SAS (side angle side congruence theorem)

5. CPCTC (congruent parts of congruent triangles are congruent)

7 0
2 years ago
Right isosceles ΔA B C has hypotenuse length h . DE is a midsegment with length 4 x that is not parallel to the hypotenuse. What
Kruka [31]

The perimeter of right isosceles ΔABC with midsegment DE is 16 + 8√2.

If right isosceles ΔABC has hypotenuse length h, then the two other sides are congruent.

side a = side b

Using Pythagorean theorem, c^2 = a^2 + b^2

h^2 = a^2 + b^2      a = b

h^2 = 2a^2

a = h/√2

If DE is a midsegment not parallel to the hypotenuse, then it is a segment that connects the midpoints of one side of a triangle and the hypotenuse. See photo for reference.

ΔABC and ΔADE are similar triangles.

a : b : h = a/2 : 4 : h/2

If a/2 = a/2, then b/2 = 4.

b/2 = 4

b = 8

If a = b, then a = 8.

If a = h/√2, then

8 = h/√2

h = 8√2

Solving for the perimeter,

P = a + b + h

P = 8 + 8 + 8√2

P = 16 + 8√2

P = 27.3137085

To learn more about midsegment: brainly.com/question/7423948

#SPJ4

5 0
1 year ago
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