Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
Answer:
(a) x = 30°
(b) mRS = 30°
mST = 120°
mTU = 120°
mUR = 90°
Step-by-step explanation:
(a) In the picture attached, the diagram is shown.
Given that m arc RS = x, from the ratios:
m arc ST = 4x
m arc TU = 4x
m arc UR = 3x
The addition of the four arcs must be equal to 360°, then:
x + 4x + 4x + 3x = 360°
12x = 360°
x = 360°/12 = 30°
(b) m arc RS = x = 30°
m arc ST = 4x = 4*30° = 120°
m arc TU = 4x = 4*30° = 120°
m arc UR = 3x = 3*30° = 90°
Answer:
The sum is 30.
Step-by-step explanation:

Answer:.
Step-by-step explanation: