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guapka [62]
2 years ago
14

(brainliest is gonna begiven answer correctly please) Use the formula V = s³, where V is the volume and s is the edge length of

the cube, to solve this problem.
A cube-shaped bin has an edge length of 12 yard.

What is the volume of the container?



Enter your answer, as a fraction in simplest form, in the box.

Mathematics
2 answers:
marysya [2.9K]2 years ago
5 0
  • Side=1/2yd

Volume:-

  • side³
  • (1/2)³
  • 1/2³
  • 1/8yd³
ad-work [718]2 years ago
3 0

Answer:

\sf  V=\dfrac18\: \sf yd^3

Step-by-step explanation:

<u>Volume of a cube formula</u>

\sf V=s^3

where:

  • V = volume
  • s = edge length

Given:

  • s = 1/2 yard

\sf \implies V=\left(\dfrac12\right)^3

Apply exponent rule (\frac{a}{b})^c=\dfrac{a^c}{b^c}

\sf \implies V=\dfrac{1^3}{2^3}

\sf \implies V=\dfrac18\: \sf yd^3

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The number of observations is 15.

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120 times 1.75 show your work plz help me I really dont get it
sineoko [7]
120 * 1.75 = 200

5 times 0 = 0

5 times 2 = 10 carry the 1

5 times 1 = 5 + 1 = 6

7 times 0 = 0

7 times 2 = 14 carry the 1...

7 times 1 = 7 + 1 = 8
1 times 0 = 0
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What is the slope and y-intercept for <br> -6x + 4y = -12
Anestetic [448]
Slope: 3/2
Y-Intercept: -3
6 0
3 years ago
Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear
AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope AB

we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

m_A_B=m_A_C

-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

simplify

x=\frac{83}{50}

8 0
3 years ago
NEED HELP!! PLEASE PLEASE
Bezzdna [24]

Answer:

The answer is A

Step-by-step explanation:

hope this helps,

If you like my answer please give brainliest,

Happy Holidays!

6 0
3 years ago
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