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Answer: 120 different ways</h3>
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Explanation:
There are...
- 6 ways to select the first place winner
- 5 ways to pick the second place winner
- 4 ways to pick the third place winner
We start with 6, and count down by 1 each time we fill up a slot. We stop once the third slot is filled or accounted for. The countdown is to ensure that we don't pick the same person twice. From here, multiply those values: 6*5*4 = 30*4 = 120
Interestingly, this is equal to 5! = 5*4*3*2*1 = 120 because the 3*2 becomes 6 and that *1 at the end doesn't affect things. Though usually results of permutation problems don't always end up like this. The order matters because a result like ABC is different from BAC, where A,B,C,D,E,F are the six school organizations.
As a slightly longer way to do the problem, you can use the nPr formula which is
where n = 6 and r = 3 in this case. The exclamation marks indicate factorial. If you go this route, you should find that one of the steps will involve 6*5*4.
Answer:
Step-by-step explanation:
Given that a seller has acquired 120 randomly selected items from a vendor for his stores. He has an allowance of 10% for damaged items. Of the 120 items acquired from the vendor, the seller found that 15 are damaged.
Population proportion= 0.10
Sample proportion = 15/120 = 0.125
To test whether the population proportion of the vendor's items exceeds the seller's allowable limit,
the hypotheses would be

(right tailed test)
So 3150÷7=450 and then multiply 450×3= 1350. So 1350 people who jog regularly