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Mars2501 [29]
3 years ago
14

Which option is a better deal? 12 ounces of cereal for $2.99 or 17ounces of cereal for $3.52

Mathematics
1 answer:
masya89 [10]3 years ago
8 0

Answer:

17 ounce cereal

Step-by-step explanation:

It is only a 53. cent difference so the better option would be the 17 ounce bag

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What does the constant 0.9955 reveal about the rate of change of the quantity?
cricket20 [7]

The model given is:

f(t)=290(0.9955)^{60t}

The term in the parentheses represents the change of rate of the model. If the number is the parentheses is less than 1, we call it <em>exponential decay</em>.

If the number in parentheses is bigger than 1, we call it exponential growth.

In this case, the correct option is "decaying"

The number in parentheses let's call it R, is:

R=1-r

Where r is the rate of change. To find it:

\begin{gathered} 0.9955=1-r \\ . \\ r=1-0.9955=0.0045 \end{gathered}

To convert to percentage, we convert by multiplying by 100::

0.0045\cdot100=0.45\%

The second answer is 0.45%

And since t is the time passed in hours, and has a "60" multiplying it, the last answer is: Every 60 hours

<em>The final answer is:</em>

The function is exponentially decaying at a rate of 0.45% evary 60 hours.

7 0
1 year ago
–6 + 4k = 2(–2k + 5) + 6k
balu736 [363]

Answer:

k=8

Step-by-step explanation:

yes

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3 years ago
Chloe ate 10 grapes and 5 crackers. Layla ate 5 grapes and 10 crakers. Who ate more food items? Write a number sentence. Then id
a_sh-v [17]
10+5=5+10
They both ate the same amount of food. 
Commutative Property of Addition is used. 
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4 years ago
You are playing a game using the spinners shown.
Otrada [13]

Answer and Step-by-step explanation:

<u>You should pick Spinner A.</u> There is a high chance of getting red since there are three pieces of the spinner that has red on it, while Spinner B only has 2 instances of red.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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If the circumference of a circle is doubled, how does the diameter of the circle change?
jeyben [28]

diameter will be doubled

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