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grandymaker [24]
3 years ago
13

A circle with center at (12,−1) passes through (0,−1). Find the circumference and area of the circle in terms of p.

Mathematics
1 answer:
madreJ [45]3 years ago
6 0

Answer:

C = 75.36

A = 452.16

Step-by-step explanation:

Find the radius r by finding the distance between (12,-1) and (0,-1) using the distance formula.

d = \sqrt{(12-0)^2 + (-1--1)^2} =\sqrt{(12)^2 + (0^2} =\sqrt{144+0} =\sqrt{144}=12

The radius is 12.

So the circumference of the circle is C = 2\pi r = 2\pi 12 = 24\pi = 75.36

So the area of the circle is A = \pi r^2\\A = \pi 12^2\\A = 144\pi\\A = 452.16

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If f(x) =-2+8 and g(x) = square root of x+9 which statement is true
lidiya [134]

The statement that -6 is in the domain of f(g(x)) is true

<h3>Complete question</h3>

If f(x) = -2x + 8 and g(x) = \sqrt{x + 9, which statement is true?

  • -6 is in the domain of f(g(x))
  • -6 is not in the domain of f(g(x))

<h3>How to determine the true statement?</h3>

We have:

f(x) = -2x + 8

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Start by calculating the function f(g(x)) using:

f(g(x)) = -2g(x) + 8

Substitute g(x) = \sqrt{x + 9

f(g(x)) = -2\sqrt{x + 9} + 8

Set the radicand to at least 0

x + 9 \ge 0

Subtract 9 from both sides

x \ge -9

This means that the domain of f(g(x)) are real numbers greater than or equal to -9. i.e. -9, -8, -7, -6, ...........

Hence, the statement that -6 is in the domain of f(g(x)) is true

Read more about domain at:

brainly.com/question/24539784

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3 0
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Answer:

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Step-by-step explanation:

2 in 529 is in the tens place - 10

So if 2 is in the tens place, we have 20 as the value of 2.

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Answer:

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an easier way is, 650 ÷ 2 = 325 miles, likewise when 10 ÷ 2 = 5 hours

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