<h3>Answer: 6pi radians</h3>
(this is equivalent to 1080 degrees)
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Explanation:
f(x) = sin(x/3)
is the same as
f(x) = 1*sin( (1/3)(x-0) )+0
and that is in the form
f(x) = A*sin( B(x-C) )+D
The letters A,B,C,D are explained below
A = helps find the amplitude
B = 2pi/T, where T is the period
C = determines phase shift (aka left/right shifting)
D = determines vertical shift = midline
All we care about is the value of B as that is the only thing that is connected to the period T
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Compare f(x) = 1*sin( (1/3)(x-0) )+0 with f(x) = A*sin( B(x-C) )+D and we see that B = 1/3, so,
B = 2pi/T
1/3 = 2pi/T
1*T = 3*2pi ... cross multiply
T = 6pi
The period is 6pi radians. This is equivalent to 1080 degrees. To convert from radians to degrees, you multiply by (180/pi).
Answer:
978 in^2
Step-by-step explanation:
the area of the rectangle:
24in X 30in = 720 in^2
the area of the two similar triangles:
12 X 9 / 2 + 12 X 9 / 2 = 108 in^2
the area of the last triangle:
20 in X 15 in /2 = 150in^2
.
the total area is the sum of the areas:
720in^2 + 108in^2 + 150in^2 = 978in^2.
Answer:
The ratio of the intensities is roughly 6:1.
Step-by-step explanation:
The intensity I() of an earthquake wave is given by:
<em>where P: is the power ans d: is the distance. </em>
Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km </em>

Therefore, the ratio of the intensities is roughly 6:1.
I hope it helps you!

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