Write 127.90 in expanded form

PLEASE ANSWER QUICKLY! <br><br> Write an equation for each translation of y = |x|.<br> NUMBER 4

Leya [2.2K]

The answer is d I just did that paper mark me Brainly

3 0

3 years ago

The formula for the perimeter, P, of a rectangle is P = 2L + 2w, where L is the length and W is th width sovle the formula for t

vichka [17]

P = 2L + 2w

Subtract 2L
from each side: P - 2L = 2w

Divide each side
by 2 : (P - 2L) / 2 = w

You could also write it as (P/2 - L) = w
Both answers are the same.

4 0

3 years ago

Use the picture to figure out the 4 digit number combination.

professor190 [17]

3574 it’s the number of books each kids has

7 0

2 years ago

Read 2 more answers

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

3 years ago

Brainliest + 30 points

Evgesh-ka [11]

Answer:

10

Step-by-step explanation:

Plug the numbers into the distance formula:

$d = \sqrt{(x2 - x1)^2 + (y2-y1)^2} \\$

$d = \sqrt{(11 - 5)^2 + (16-8)^2} \\$

Then solve:

You get 10

5 0

3 years ago

Read 2 more answers