Answer:give me points
Step-by-step explanation:
Please
Answer: 28
Step-by-step explanation:
Given
Kenny made 7 serves over the net for every 2 serves that did not go over the net i.e. success rate of Kenny is
for 36 serves, applying the same success rate, it is
Serves that did not make over the net is 
Thus, Kenny will make 28 serves that make over the net
Let c represent the original amount that this guy had saved up.
He spent 25% of this amount, or 0.25c, on the printer.
To progress further, we have to know how much the printer cost.
Supposing that the printer cost $100 (which we do not know as a fact), this would be equal to 0.25c.
Thus, his savings originally amounted to c = $100/0.25 = $400.
Answer:
The factors are (5x + 3) and (2x + 1)
Step-by-step explanation:
When you need to factor a quadratic, and the coefficient of the x² is not 1, use the slide and divide method.
The general form of a quadratic is ax² + bx + c
Factor: 10x² + 11x + 3
Here a = 10, b = 11, and c = 3
Step 1: Multiply ac, we SLIDE a over to c. Notice the 10 is gone for now..
x² + 11x + 30
Step 2: Factor this (this step will always factor)
x² + 11x + 30 = (x + 5)(x + 6)
So the factors are (x + 5)(x + 6), but we now need to DIVIDE by a, since we multiplied it into c before. We divide the constants in the factors...
(x + 5/10 )(x + 6/10 )
Now reduce the fractions as much as possible...
(x + 1/2 )(x + 3/5)
*If they don't reduce to a whole number, SLIDE the denominator over as a coefficient of x....
(2x + 1)(5x + 3) *2 slide over in front of x, 5 slide over in front of x, the fractions are gone!
These are our factors!
Answer:
A
Step-by-step explanation:
clearly, the equation has to allow t=0, and for that point we need to get 100% (of carbon-14) as result.
and so we also see, that the function calculates the % of the remaining carbon-14.
so, we need the desired outcome 60(%),
because 60 = 100 - 40.
and again, we need a function that shows t=0.
the only answer option fulfilling both criteria is A.
B divides in the exponent by t, so t=0 is not in the domain of the function.
and C and D aim for the wrong remaining percentage.
