Bill should put the brackets around 18-9 so the correct answer is option B. 10- 4 +3 x (18-9)
Area of the canvas: 96 = 2 · W² + 2 · W L,
where W is the width and L is the length of a back and a top side. Two square sides have area W².
2 W L = 96 - 2 W² /:2
W L = 48 - W²
L = ( 48 - W² ) / W.
The inside volume of the shelter:
V = L · W · W = L · W²
V = W² · ( 48 - W² ) / W ;
V = 48 W - W³
We have to find the derivative:
V ` = 48 - 3 W²
48 - 3 W² = 0 ( for V max. )
3 W² = 48
W² = 48 : 3
W² = 16; W = √16; W = 4 ft.
L = ( 48 - 16 ) / 4 = 32 / 4 = 8 ft.
Answer: The length of the shelter for which the volume inside is maximized is 8 ft.
70% because there are 7 out of the 10 years that have more than 5 inches of rain so you do 7/10 x 100 = 70%
Answer:
4
Step-by-step explanation:
-3(4x +3)+4(6x +1)=43
-12x-9 +24x +4 =43
12x - 5=43
12x=43 +5
12x=48
x=48 :12
x=4
