we are given

now, we can compare it with

we can find b
we get

now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8

b=1.6

b=1.4

b=1.2

now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
The answer is A.payments are directly deducted from your account
Answer:
y = 1/7x + 88/7
Step-by-step explanation:
y = mx +b
since it is perpendicular you have to get the negative reciprocal of the slope which is 1/7
y = 1/7x + b then you would plug in your points
12 = 1/7(-4) + b and then solve for b
12 = -4/7 + b
+ 4/7
88/7 = b
y = 1/7x + 88/7
Yeah but what is the question?
There were<span> 471 </span>adult<span> and 851 </span><span>student tickets sold</span>