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Olegator [25]
3 years ago
8

if a recipe for cookies calls for 3/4 of a cup of sugar, and you want to quadruple the recipe, how many cups of sugar will you n

eed?
Mathematics
2 answers:
Lemur [1.5K]3 years ago
7 0
You will need 3 cups of sugar.
Misha Larkins [42]3 years ago
7 0
You will need 3 cups of sugar because (3/4)(3/4)(3/4)(3/4)= 12/4 which gives you 3
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Help me please! If you DO decide to help, please explain it to me since I'm extremely confused! THANK YOU!
den301095 [7]

\bf \cfrac{(-4x^2)(2x^{-2}y)^3}{(16x^5)(4y^3)^2}\implies \cfrac{(-4x^2)(2^3x^{-2\cdot 3}y^3)}{(16x^5)(4^2y^{3\cdot 2})}\implies \cfrac{(-4x^2)(8x^{-6}y^3)}{(16x^5)(16y^6)} \\\\\\ \cfrac{-32x^{2-6}y^3}{256x^5y^6}\implies -\cfrac{x^{-4} y^3}{8x^5y^6}\implies -\cfrac{1}{8x^5x^{4}y^6y^{-3}}\implies -\cfrac{1}{8x^{5+4}y^{6-3}} \\\\\\ -\cfrac{1}{8x^9y^3}

8 0
3 years ago
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I Give brainliest.<br><br>PLEASE PLEASE PLEASE PLEASE PLEASE HELP ME!!!
ryzh [129]
The answer is, 2/5 and 3/2
6 0
3 years ago
A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte
ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, q_1 = Q- r \times Q

q_1 = Q(1-r)\cdots(i)

The value of quantity after 2 months, q_2 = q_1- r \times q_1

q_2 = q_1(1-r)

From equation (i)

q_2=Q(1-r)(1-r)  \\\\q_2=Q(1-r)^2\cdots(ii)

The value of quantity after 3 months, q_3 = q_2- r \times q_2

q_3 = q_2(1-r)

From equation (ii)

q_3=Q(1-r)^2(1-r)

q_3=Q(1-r)^3

Similarly, the value of quantity after n months,

q_n= Q(1- r)^n

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

q_{48}=Q(1-r)^{48}

Putting Q=6200 and r=5.5%=0.055, we have

q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32

Hence, the value of quantity after 4 years is 410.32.

4 0
3 years ago
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Round to the nearest tenth.<br><br> x= <br><br> y=
11111nata11111 [884]
I could be wrong but I’m pretty sure x≈102.2 and y≈58
6 0
3 years ago
Which equation is equivalent to logx 36 = 2?​
Margaret [11]

Answer:

The answer would be 36^2=x

Step-by-step explanation:

5 0
3 years ago
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