<h2>
Answer:</h2>
Option: C is the correct answer.
C.) x = −3.8, 3
<h2>
Step-by-step explanation:</h2>
The function f(x) is given by:

and the function g(x) is given by:

Now, we are asked to find the solution of the equation:

i.e. we have to find the value of x such that both the functions are equal i.e.

Now, on solving the equation using the quadratic formula i.e. the solution of the equation:

is given by:

Here we have:

Hence, the solution is given by:

The height and radius that will give us the smallest amount of paper, should have should have the perfect dimension, in that the diameter should be equal to the height. thus let the diameter be x, the height will be x and the radius will be x/2
thus the volume of the cone will be:
V=1/3πr^2h
=1/3*π*(x/2)^2*x
=0.262x^3
hence the value of x will be:
33=0.262x^3
x^3=125.95
x=(125.95)^(1/3)
x=5.0126=5.01 cm
thus the diameter=height=5.01cm
Factor out the GCF. Do not forget to include the GCF as part of your final answer. In this case, the three terms have a 3x in common, which leaves: Step 3: Multiply the leading coefficient and the constant, that is multiply the first and last numbers together.
Answer:
See below
Step-by-step explanation:
1..........................
Add –5; 2.7; 7 to both sides
- 18 -5 > -7 - 5 ⇒ 13 > -12
- 18 + 2.7 > - 7 + 2.7 ⇒ 20.7 > - 43
- 18 + 7 > -7 + 7 ⇒ 25 > 0
2..........................
Subtract 2; 12; -5 from both sides
- 5 - 2 > -3 -2 ⇒ 3 > - 5
- 5 - 12 > -3 - 12 ⇒ -7 > -15
- 5 -(-5) > -3 - (-5) ⇒ 10 > 2
3..........................
Multiply both sides by 3; −3; −1
<em>When multiplying both sides of inequality by positive number the sign stays as is, when multiplying both sides of inequality by negative number the sign reverses</em>
- -9 *3 < -6*3 ⇒ -27 < - 18
- -9*(-3) > -6*(-3) ⇒ 27 > 18
- -9*(-1) > -6*(-1) ⇒ 9 > 6
Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3