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2 years ago

8

A beach ball has a radius of 9 inches. find the volume of the beachball, in cubic inches and round the answer to the nearest who

le number

2 answers:

boyakko [2]2 years ago

8 0

3053.63 which would be rounded to 3054.

lesya692 [45]2 years ago

7 0

V=4/3pi(r^3)
V=4/3pi(9^3)
V=3,054 inches^3

Think this is right

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faust18 [17]

45 degreesssss please brainliest answer plsss.

8 0

2 years ago

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

Evaluate the expression<br><br> x^2 (y - 2)<br> —————, if x=3, and y= -1<br> 3y

vitfil [10]

Answer:

$\huge\boxed{\sf 9}$

Step-by-step explanation:

$\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>

4 0

2 years ago

Read 2 more answers

What the heck do i do with this

timurjin [86]

I forgot how to do this sorry

5 0

3 years ago

How can I figure out this math problem: Stanley ran a 5 kilometer race in 30 minutes. What was his speed in kilometers per hour?

stiv31 [10]

Since the question is asking for the time units to be in hours, you want to convert 30 minutes to an hour; 0.5

We’re able to use the basic motion formula for velocity to work out this question.

Velocity = distance / time
Velocity = 5 / 0.5
Velocity = 10km/h

Therefore, Stanley’s average speed was 10 kilometres per hour. :)

3 0

2 years ago