Question

Let a and b 2 positive real number such that a

Answer 1

Answer:

Proved

Step-by-step explanation:

Given

Integers: a and b

Where $a < b$

Required

Show that $a^n < b^n$

We start by writing out the given expression

$a < b$

Then, take nth root of both sides

$a^n < b^n$

For instance:

Let a = 2,  b = 2 and n = 4

First

Since $2 < 3$

Then

$2^4 < 3^4$

$16 < 81$

Proved

This is so for all positive values of a,b and n where a < b