Answer:
A. 3 < t < 9
Step-by-step explanation:
When the particle is moving to the right, the velocity is positive.
To find the velocity, take the derivative of s(t) with respect to t.
s(t) = -t³/3 + 13t²/2 − 30t
s'(t) = -t² + 13t − 30
Find when the velocity is 0.
0 = -t² + 13t − 30
0 = t² − 13t + 30
0 = (t − 3) (t − 10)
t = 3, 10
Check the sign of s'(t) in each interval.
0 < t < 3, s'(t) < 0
3 < t < 9, s'(t) > 0
The particle moves to the right when 3 < t < 9.
Hmm I read it over and over and I don't exactly understand what they're asking?
So it starts by 22.50 regularly so she worked 40 regular hours so $22.50 * 40h= $900 and in over time she gets double for working over time so $22.50 * 2 = $45 and she worked 12 hours so 12h * $45 = $540 then we need to add those two numbers up 900 + $540 = $1,440 is our answer/outcome.
Answer: B) 400/3 Pi ft^3
Step-by-step explanation:
V=πr2h
3=π·52·16
3≈418.87902
and
400
/3
(3.141593)
=418.87902
so its B
