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3 years ago

I need helpppp plssss anyone I’m not the best at math :/

Mathematics

1 answer:

Ulleksa [173]3 years ago

7 0

Answer:

Step-by-step explanation:

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PLEASE HELP!! I will make you brainlest.

Dmitry [639]

Answer:

Question 13: 90, Question 14: y = $3\sqrt{10}$ , Question 15: x = $17\sqrt{3}$ , Question 16: y = $34\sqrt{3}$ .

Step-by-step explanation:

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3 years ago

21) PLEASE HELP WITH QUESTION. WILL MARK BRAINLIEST + POINTS.

LenKa [72]

8
Suppose f(x) = ----------
sqrt(x)
8
What if we let x = 16 (just an example)? We'd get f(16) = ------------- = 2.
sqrt(16)

What if we let x = g(x) = 2x+4?

We'd get the following:

8
f(g(x)) = -------------- = y
sqrt(2x+4)

So...the correct answer is the fourth one.

5 0

3 years ago

What is the solution to the equation?

UkoKoshka [18]

$\frac{1}{3}x+\frac{1}{3}(2x-15)=3\frac{1}{2}\\\\
\frac{1}{3}x+\frac{1}{3}(2x-15)=\frac{7}{2}\ \ \ |Multiply\ by\ 6\\\\
2x+2(2x-15)=21\\\\
2x+4x-30=21\\\\
6x-30=21\ \ |Add\ 30\\\\
6x=51\ \ \ |Divide\ by\ 6\\\\
\boxed{x=\frac{51}{6}=8\frac{1}{2}}$

7 0

3 years ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.)

joja [24]

Answer:

$\int_{-1}^{1}7(x^{3}-x)\:dx$

Step-by-step explanation:

1) The other curve is $y=0$ then the common points of both curves are x-intercepts, the roots of $y=7(x^{3}-x)$

$y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )$

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

$\int_{a}^{b}|f(x)-g(x)dx$

$\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx$

8 0

3 years ago

A surveyor measures a road as being 69.3km long, however there is a 1℅ error in this measurement .What is the true length of the

Vaselesa [24]

Answer:

69.993

Step-by-step explanation:

Using the percentage error formula:

Percentage error = (true - measured value / true measurement ) * 100%

1% error in measurement

1% of 69.3

0.01 * 69.3 = 0.693

True measurement = error in measurement + measured value

True measurement = 0.693 + 69.3

Actual measurement = 69.993

Hence, actual measurement = 69.993.

5 0

3 years ago