hi it could be 3x+2=180 , 3/4x+19=189, 3.4x+12=100
Answer:
![a_n=100 \left(\dfrac15\right)^{n-1}](https://tex.z-dn.net/?f=a_n%3D100%20%5Cleft%28%5Cdfrac15%5Cright%29%5E%7Bn-1%7D)
Step-by-step explanation:
General equation of geometric sequence: ![a_n=ar^{n-1}](https://tex.z-dn.net/?f=a_n%3Dar%5E%7Bn-1%7D)
Given:
![\implies a_1=a=100](https://tex.z-dn.net/?f=%5Cimplies%20a_1%3Da%3D100)
![\implies a_2=100 \cdot r=20](https://tex.z-dn.net/?f=%5Cimplies%20a_2%3D100%20%5Ccdot%20r%3D20)
![\implies a_3=100 \cdot r^2=4](https://tex.z-dn.net/?f=%5Cimplies%20a_3%3D100%20%5Ccdot%20r%5E2%3D4)
Common ratio:
![r=\dfrac{a_3}{a_2}=\dfrac{4}{20}=\dfrac15](https://tex.z-dn.net/?f=r%3D%5Cdfrac%7Ba_3%7D%7Ba_2%7D%3D%5Cdfrac%7B4%7D%7B20%7D%3D%5Cdfrac15)
Therefore:
![a_n=100 \left(\dfrac15\right)^{n-1}](https://tex.z-dn.net/?f=a_n%3D100%20%5Cleft%28%5Cdfrac15%5Cright%29%5E%7Bn-1%7D)
Answer:
A
Step-by-step explanation:
40/100+ 3/10 AKA 30/100=70/100
subtract 70 from 100 and you get 30
so 30/100 donuts are cinnamon
hope that helps
If A=750+135N; and B=485N, then A+B=
750+135N+485N=750+620N
T=620N+750
☺☺☺☺