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Mkey [24]
3 years ago
14

No time is thinking of a six digit number in which all the digits are the same the value of the digit in the thousands place is

8000 what is new Times number
Mathematics
1 answer:
ipn [44]3 years ago
7 0

Answer:

The number is 888888

Step-by-step explanation:

Here, we are interested in knowing the six digit number thought of by No time.

The clue we have here is that the six digit number has same value of digit for all its constituent.

Thus, if the digit in the thousands place is 8,000, then it actually means that it carries a value of 8 and thus, all the digits in the number is 8 alone.

So the 6 digit number is 888888

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How do I solve for b.
Arturiano [62]
Since d is being subtracted from bc, we first add d to each side. Now we are left with a + d = bc.
Since b is being multiplied by c to be bc, we divide both sides by c.
We now have a/c + d = b
Your solution is: b = a/c + d
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Jared's battery has 4/25 percent of life left. Edward's battery has 3/25 percent of life left. Who has the most battery life lef
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3 years ago
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What is 10 exponent 2+24 divided (12-2 exponent 3)???
pychu [463]

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106

Step-by-step explanation:

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2 years ago
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Identify the x-intercepts of the function below f(x)=x^2+12x+24
damaskus [11]

<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here, for (1) a = 1, b= 12 and c = 24

X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

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