The frame is at each side of the picture so the area is (25 + 2x) times (32 +2x), (which multiplies out to 4x^2 + 114x + 800 square inches). ie if the frame <span>is an inch and a half wide then the area is 28 x 35 sq ins, ie 980 sq ins.</span>
Answer:
0.5?
Step-by-step explanation:
Answer:
The surface of the prism is 84m²
Step-by-step explanation:
You have 4 figures here (two the same triangles)
you need to determine the surface of each and then sum it to one. This will be your final surface.
rectangles:
3*6= 18m²
5*6 = 30m²
4*6 = 24m²
triangles:
You need to determine the square of the triangles from the Heron's formula.
Heron's formula states that the area of a triangle whose sides have lengths a, b, and c is
,
where s is the semi-perimeter of the triangle; that is,
.
So the permimeter of the triangle is
2p=4+5+3 = 12m
p = 6m
![S = \sqrt{p*(p-a)*(p-b)*(p-c)} = \sqrt{6*(6-3)*(6-4)*(6-5)} = \sqrt{6*3*2*1} =\sqrt{36} =6[m^{2} ]](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%7Bp%2A%28p-a%29%2A%28p-b%29%2A%28p-c%29%7D%20%20%3D%20%5Csqrt%7B6%2A%286-3%29%2A%286-4%29%2A%286-5%29%7D%20%20%3D%20%5Csqrt%7B6%2A3%2A2%2A1%7D%20%3D%5Csqrt%7B36%7D%20%3D6%5Bm%5E%7B2%7D%20%5D)
So the surface of the prism is a total sum of all surfaces:
P = 18m²+30m²+ 24m²+2*6m² = 84m²