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3 years ago

Solve the system by substitution. y=−3x-2 -7x+3y=10 PLEASE HELP

1 answer:

7 0

Y=-3x-2
subsitute -3x-2 for y
-7x+3(-3x-2)=10
distribute
a(b+c)=ab+ac
3(-3x-2)=-9x-6

-7x-9x-6=10
add like terms
-16x-6=10
add 6
-16x=16
multiply -1
16x=-16
divide 16
x=-1

subsitute
y=-3x-2
y=-3(-1)-2
y=3-2
y=1

x=-1
y=1

(x,y)
(-1,1)

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Let f(x)=7x-13. Find f^-1(x).

vitfil [10]

Ok but allow my humble self to use $y$ instead of $f(x)$ .

We have,

$y=7x-13$

If you wanna know what the inverse is swap the values of x and y,

$x=7y-13$

And now solve for y,

$x+13=7y\implies\boxed{y=f^{-1}(x)=\frac{x+13}{7}}$ .

Hope this helps.

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3 years ago

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Give the difference of 8/13 and 5/13 A. 3/13 B. 8/13 C. 5/13

nikitadnepr [17]

Answer:

3/13

Step-by-step explanation:

8/13 subtract by 5/13. If the denominator is the same, you keep it, don't change it. Just subtract the numerator.

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1 year ago

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Rudik [331]

Answer:

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2 years ago

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Please help!!!!due at 11 .I think the number of sodas sold was 48 but I don't know how many hotdogs were sold

Alex Ar [27]

Answer:

Number of sodas sold: 78

Number of hot dogs sold: 24

Step-by-step explanation:

Number of sodas sold = x

Number of hot dogs sold = x - 54

Total number of sodas and hot dogs = x + x - 54 = 2x - 54

Total number = 102

2x - 54 = 102

2x = 156

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Number of sodas sold = x = 78

Number of hot dogs sold = x - 54 = 78 - 54 = 24

Answer:

Number of sodas sold: 78

Number of hot dogs sold: 24

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2 years ago

If the perimeter of this triangle is to be no more than 77 feet, write an inequality and

Sergio039 [100]

Given:

Consider the sides of the triangle are 4x+10, 2x-5 and 18 (in feet).

Perimeter of this triangle is to be no more than 77 feet.

To find:

The inequality and solution of the inequality.

Solution:

Perimeter of a triangle is the sum of all side.

Perimeter of given triangle $=(4x+10)+(2x-5)+18$

Perimeter of this triangle is to be no more than 77 feet. It means perimeter must be less than or equal to 77.

$(4x+10)+(2x-5)+18\leq 77$

$(4x+2x)+(10-5+18)\leq 77$

$6x+23\leq 77$

$6x\leq 77-23$

$6x\leq 54$

Divide both sides by 6.

$x\leq \dfrac{54}{6}$

$x\leq 9$

Therefore, the required inequality is $(4x+10)+(2x-5)+18\leq 77$ and the solution is $x\leq 9$ .

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3 years ago