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aleksklad [387]
3 years ago
13

Please help me 60 points please show all work this is due in 15 minutes

Mathematics
2 answers:
harkovskaia [24]3 years ago
7 0
1. 5x-(3x-6)=18
5x-3x+6=18
2x=12
X=6

6. X/-3=8
(-3) x/-3= 8(-3)
X= -24
Alla [95]3 years ago
6 0

Answer:

Step-by-step explanation:

2. 2(3x+4)=10

6x+8=10

6x+8-8=10-8

6x=2

x= 1/3

3.  2x + 7 = 5x + 16

7 + 2x = 5x + 16

7 + 2x = 16 + 5x

7 + 2x + -5x = 16 + 5x + -5x

7 + -3x = 16 + 5x + -5x

7 + -3x = 16 + 0

7 + -3x = 16

7 + -7 + -3x = 16 + -7

0 + -3x = 16 + -7

-3x = 16 + -7

-3x = 9

x = -3

4.   x/3-8=-2

x/3=6

x=18

5. 3x-6=-12

3x-6+6=-12+6

3x=-6

x=-2

sorry but i cannot solve 1 or 6 because i am quite stupid

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<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units</h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and      y_3=8

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                          = \sqrt{(2-12)^{2} +(1-8)^2}

                         =\sqrt{149} units

Let the perpendicular distance from B to AC be = x

According To Problem

\frac{1}{2} \times  x \times \sqrt{149} = 54

⇔x =\frac{108}{\sqrt{149} } units

Therefore the perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units

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