Answer:
Length= 19 yd
Width= 15 yd
Step-by-step explanation:
The perimeter of a rectangle is the sum of the lengths of all its sides.
Mathematically, it can be represented as below:

Define variables used:
Let the length and width of the rectangle be L and W yards respectively.
Form an equation:
Given that the length of the rectangle is 4 yards longer that the width,
L= W +4 -----(1)
Next, form another equation using information on the perimeter.
68= 2(L +W) -----(2)
Substitute equation (1) into (2):
68= 2(W +4 +W)
68= 2(2W +4)
Divide both sides by 2:
34= 2W +4
Subtract both sides by 4:
2W= 34 -4
2W= 30
Divide both sides by 2:
W= 30 ÷2
<u>W= 15</u>
Substitute W= 15 into (1):
L= 15 +4
<u>L= 19</u>
Therefore, the length and width of the rectangle is 19 and 15 yards respectively.
Additional:
For another question on perimeter of rectangle, check out: brainly.com/question/15528005
15x, because 2 × 4x= 8x and -1×-7=7x...add 8x and 7x ull get the answer
Math I hate math bc it sucks
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3/2x-7=-11
We move all terms to the left:
3/2x-7-(-11)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
3/2x+4=0
We multiply all the terms by the denominator
4*2x+3=0
Wy multiply elements
8x+3=0
We move all terms containing x to the left, all other terms to the right
8x=-3
x=-3/8
x=-3/8